All categories

3 years ago

What xDSL version provides a maximum throughput of 24 Mbps downstream and 3.3 Mbps upstream?

Computers and Technology

1 answer:

slamgirl [31]3 years ago

3 0

The answer is ADSL2+M which also happens to be the latest version of the ADSL2+.

DSL (Digital Subscriber Line) technology is common in bringing broadband info to residential and small businesses over copper telephone lines. It comes with many flavors like ADSL and SDSL. The most common used is ADSL and ADSL2+ in most countries. ADSL is able to offer speeds of up to 8Mbps downstream and 448 Kbps upstream.

The Latest ADSL2+ is able to push speeds of up to 24Mbps downloads and 1.4Mbps uploads. Technically, ADSL2+M is the common name for the ADSL2+ and is to push 24Mbps UP and 3.3Mbps DOWN

You might be interested in

scientist think that two species with homologous structures probably had ____ A. Ancestor B. Fossil C. Environment D. Offspring

Naddika [18.5K]

The answer is A: ancestor

4 0

3 years ago

Write a statement that increments numUsers if updateDirection is 1, otherwise decrements numUsers. Ex: if numUsers is 8 and upda

Lady_Fox [76]

Answer:

Following are the statement is given below

if(updateDirection ==1) // check condition

{

++numUsers; // increments the value

}

else

{

--numUsers; // decrement the value

}

Explanation:

Following are the description of statement

Check the condition in the if block .If the "updateDirection" variable is 1 then then control moves to the if block otherwise control moves to the else block statement.

In the if block the statement is "++numUsers" it means it increment the value by 1 .

In the else block the statement is "--numUsers" it means it decrement the value by 1 .

4 0

3 years ago

When comparison shopping, all of these hint at a good deal EXCEPT_____________________.

noname [10]

Answer:

lower-priced models offer more features

Explanation:

3 0

3 years ago

Create a structure representing a student. The member variables should include student name, student ID, and four test grades fo

Neporo4naja [7]

Answer:

Output:

Name: Brainly

ID:0001

Write the 4 tests grades of the student separated by space :10 9 8 10

Brainly

0001

10 9 8 10

Average :9.66667

'1' to continue '0' to exit :

Explanation:

#include<iostream>

#include<string>

using namespace std;

//variables declaration

struct Student {

string id; //string declaration ID

string name; // string declaration name

int grades[4]; //array of 4 because it is 4 grades

};

//definition of the function get information

void inputData(Student &s){

cout << "Name:" ;

getline(cin,s.name);

cout << "ID:";

cin >> s.id;

cout << "Write the 4 tests grades of the student separated by space :";

for (int i = 0; i<4; i++)

cin >> s.grades[i];

}

//definition of the function of average

double inputAvg(Student s){

double summation;

int temporary;

double average;

for (int i = 0; i<4; i++){

for (int j = i; j<4; j++){

if (s.grades[j] > s.grades[i]){

temporary = s.grades[i];

s.grades[i] = s.grades[j];

s.grades[j] = temporary;

}

summation = 0;

for (int i = 0; i<3; i++){

summation = summation + s.grades[i];

}

average = summation/3;

return average;

}

void disp(Student *s){

cout << s->name << endl;

cout << s->id << endl;

for (int i = 0; i<4; i++)

cout << s->grades[i] << " ";

cout << endl;

cout << "Average :" << inputAvg(*s) << endl;

}

int main(){

Student st;

int ch;

while(true){

inputData(st);

disp(&st);

cout << " '1' to continue '0' to exit :";

cin >> ch;

if (ch == 0)

break;

}

return 0;

}

6 0

3 years ago

write an algorithm and draw a flowchart for switching off a machine after it has made 500 glass bottles. use an appropriate cond

Anni [7]

Answer:

The algorithm is as follows:

1. Start

2. bottles = 0

3. While bottles != 500

3.1 Create bottle

3.2 bottle = bottle + 1

4. Switch off machine

5. Stop

See attachment for flowchart

Explanation:

This begins the algorithm

1. Start

This initializes bottles to 0

2. bottles = 0

The loop is repeated until 500 bottles is created

3. While bottles != 500

This creates a new bottle

3.1 Create bottle

This increments the number of bottles by 1

3.2 bottle = bottle + 1

This switches of the machine after all bottles are created

4. Switch off machine

End algorithm

5. Stop

7 0

3 years ago