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3 years ago

Will give brainliest to correct answer

Mathematics

1 answer:

yanalaym [24]3 years ago

5 0

Answer:

A or B or C or D, one of those

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Which is greater 3.260 or 3.206

Sati [7]

Answer:

3.260 is greater.

Step-by-step explanation:

The ones place is the same, the tenths place is the same, the hundredths place is different. 3.260 has a greater hundredths place, so 3.260 > 3.206

7 0

3 years ago

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The volume of a beack ball is 905 square centimeters. Find the radius of the ball to the nearest whole number.

lubasha [3.4K]

<h3>given:</h3>

$v = 905 \: {cm}^{3}$

the radius of the given ball (sphere).

<h3>solution:</h3>

$r = \sqrt[3]{ \frac{3v}{4\pi} }$

$r = \sqrt[3]{ \frac{3 \times 905}{4\pi} }$

$r = 6 \: cm$

therefore, the radius of the ball is 6 cm.

note: refer to the picture I added on how you can change r as the subject of the formula.

8 0

2 years ago

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Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

7 0

1 year ago

Is y = 0.5x - 1 a liner function

Mama L [17]

$\text{Yes, it is a linear function}\\\\\text{The reason why it's a linear function is because there is a constant change}\\\\\text{The constant change would be your slope, and the slope in this case}\\\text{is 0.5}\\\\\text{If you plug this equation in a graph, it would be a straight line forever}\\\\\text{If you want to know if a line is linear, just check the slope to see if it's}\\\text{constant.}$

8 0

3 years ago

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Change x + 2y = 6 into slope-intercept form.

mart [117]

Answer:

The slope intercept form involves solving for y, such that the equation looks like this: y = mx + b, where m is a constant representing the slope of the line, and b is a constant representing the value of the y-intercept.

Starting with the equation x+2y=6 and subtracting x from both sides gives 2y = -x + 6.

If we then divide each term by 2, we get the final result of y = -1/2x + 3.

Here we see that the slope (m) is equal to -1/2, and the y-intercept (b) is 3.

Step-by-step explanation:

4 0

3 years ago

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