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lilavasa [31]
3 years ago
10

wiĺla's rectangular patio has an area of 36m, and whole area side lengths. what might the length and width of the atio be? give

3 possible answers.
Mathematics
1 answer:
Vinil7 [7]3 years ago
5 0
The length can be 18 and the width can be 2.
18 x 2 = 36
Or the length can be 12 and the width can be 3.
12 x 3 = 36
The length can also be 9 and the width can be 4.
9 x 4 = 36
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Can someone please tell me the answer on this.
marishachu [46]

Answer: x = 31

Step-By-Step:

<u>To Find x:</u>

<u />\left(2x+20\right)+\left(x+10\right)+\left(2x-5\right)=180 (Angle Sum Property Of Triangles)

(Remove the brackets)

<u />2x+20+x+10+2x-5=18<u />

(Group Accordingly)

<u />2x+x+2x+20+10-5=180<u />

= 5x+20+10-5=180

= 5x\:+\:25 =180

= 5x= 180 - 25

= 5x = 155

= x=\frac{155}{5}

= 31

<u>Therefore</u> x = 31

So,

Angle A = x + 10 = 31 + 10 = 41

Angle B = 2*x + 20 = 2*31 + 20 = 82

Angle C = 2*x - 5 = 62 - 5 = 57

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2 years ago
a) Estimate the volume of the solid that lies below the surface z = 7x + 5y2 and above the rectangle R = [0, 2]⨯[0, 4]. Use a Ri
SSSSS [86.1K]

In the x direction we consider the m=2 subintervals [0, 1] and [1, 2] (each with length 1), while in the y direction we consider the n=2 subintervals [0, 2] and [2, 4] (with length 2). Then the lower right corners of the cells in the partition of R are (1, 0), (2, 0), (1, 2), (2, 2).

Let f(x,y)=7x+5y^2. The volume of the solid is approximately

\displaystyle\iint_Rf(x,y)\,\mathrm dx\,\mathrm dy\approx f(1,0)\cdot1\cdot2+f(2,0)\cdot1\cdot2+f(1,2)\cdot1\cdot2+f(2,2)\cdot1\cdot2=\boxed{164}

###

More generally, the lower-right-corner Riemann sum over m=\mu and n=\nu subintervals would be

\displaystyle\sum_{m=1}^\mu\sum_{n=1}^\nu\left(7\frac{2m}\mu+5\left(\frac{4n-4}\nu\right)^2\right)\frac{2-0}\mu\frac{4-0}\nu=\frac83\left(101+\frac{21}\mu+\frac{40}{\nu^2}-\frac{120}\nu\right)

Then taking the limits as \mu\to\infty and \nu\to\infty leaves us with an exact volume of \dfrac{808}3.

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