5x + 4y = 32 ⇒ 45x + 36y = 288
9x - 1y = 33 ⇒ <u>45x - 5y = 165</u>
<u>41y</u> = <u>123</u>
41 41
y = 3
5x + 4(3) = 32
5x + 12 = 32
<u> - 12 - 12</u>
<u>5x</u> = <u>20</u>
5 5
x = 4
(x, y) = (4, 3)
O = 7*180 = 1260 degrres
sin O = 0
2x² - 3xy
2(1)² - 3(1)(2)
2(1) - 3(2)
2 - 6
-4
Answer:
0.322 × 10¹² /L
Step-by-step explanation:
Data provided in the question:
Number of cells counted with blue-stained granulofilamentous material
i.e number of RET = 100
The red blood cells count = 3.22 × 10¹² /L
Hematocrit = 30%
Now,
RET% = [ [ Number of RET ] ÷ 1000 RBCs ] × 100%
= [ 100 ÷ 1000 ] × 100%
= 0.1 × 100%
= 10%
also,
Absolute reticulocyte count = ( %RET × RBC count ) ÷ 100
= [ 10 × 3.22 × 10¹² /L ] ÷ 100
= 0.322 × 10¹² /L
3t+9≥15 => 3t ≥ 6 => t ≥2 => t= [2,∞)
Hope that helps, have a nice day!! ^^
