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velikii [3]
3 years ago
7

In football, a kicker can score one point for the extra-point on a touchdown or three points for a field goal.

Mathematics
1 answer:
White raven [17]3 years ago
3 0
I am not sure but i will try to help

In football, a kicker can score one point for the extra point on a touchdown or three points for a field goal. logan is a kicker for his high school football team. the record number of points scored by a kicker in a single game is 24
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D- It is an enlargement with a scale factor greater than 1.

From the pre-image to the image, the scale factor is 3.
5 0
3 years ago
Evaluate the expression 3x^2+4x^3 when x=4.
larisa [96]

Step-by-step explanation:

304

plug 4 in for x

3(4)^2 + 4(4)^3 = 304

48 + 256 = 304

6 0
3 years ago
25 Points, will give brainliest
miskamm [114]

Answer:

B. 434.89

Step-by-step explanation:

A basketball is a sphere and the volume formula is:

V = 4/3πr³

Given:

d = 9.4

r = 9.4/2

r = 4.7

Work:

V = 4/3πr³

V = 4/3π(4.7)³

V = 4/3π(103.823)

V = 434.89

3 0
2 years ago
Choose the amount of money that is equal to 1 dollar 1 nickel.
Kaylis [27]
First one because 20 nickels = 1$ and 1 nickel is = 5€
6 0
2 years ago
How much would you invest today to have $9500 in 8 years if the effective annual rate of interest is 4%?
aniked [119]

Answer:

a) You should invest $6941.90 today.

b) The effective annual interest rate is 11%.

c) t is approximately 6.

Step-by-step explanation:

These are compound interest problems. The compound interest formula is given by:

A = P(1 + \frac{r}{n})^{nt}

Where A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit t and t is the time the money is invested or borrowed for.

a) How much would you invest today to have $9500 in 8 years if the effective annual rate of interest is 4%?

Here, we want to find the value of P when A = 9500, t = 8, n = 1, r = 0.04.

9500 = P(1 + \frac{0.04}{1})^{8}

P = \frac{9500}{1.3685}

P = 6941.90.

You should invest $6941.90 today.

b) Suppose that an investment of $5750 accumulates to $11533.20 at the end of 13 years, then the effective annual interest rate is i= ?

Here, we have that A = 11533.20, P = 5750, t = 13, n = 1, and we want to find the value of i, that is r on the formula above the solutions.

11533.20 = 5750(1 + r)^{13}

\sqrt[13]{11533.20} = \sqrt[13]{5750(1 + r)^{13}}

2.05 = 1.94(1 + r)

r = 0.11

The effective annual interest rate is 11%.

c) At an effective annual rate of interest of 5.3%, the present value of $7425.70 due in t years is $3250. Determine t.

Here, we have that A = 7425.70 + 3250 = 10675.7, P = 7425.7, r = 0.053, n = 1 and we have to find t. So

10675.7 = 7425.7(1 + \frac{0.053}{1})^{t}

(1 + 0.053)^{t} = \frac{10675.7}{7425.7}

(1.0553)^{t} = 1.4377

We have that:

log_{a}a^{n} = n

So

log_{1.0553} (1.0553)^{t}  = log_{1.0553} 1.4377

t = 5.95

t is approximately 6.

8 0
3 years ago
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