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miss Akunina [59]
3 years ago
8

What is the Scientific notation of 1,678,483.0043

Mathematics
2 answers:
Ksju [112]3 years ago
6 0
1\underbrace{,678,483.}_{\leftarrow6}0043=1.6784830043\times10^6

harkovskaia [24]3 years ago
4 0
the\ scientific\ notation:\ \ \ a\cdot 10^n\ \ \ and\ \ \ a\in\langle1,10),\ \ \ n\in I\\\\1,678,483.0043=1.6784830043\cdot10^6
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Find the values of x when y=1
kirill [66]

Answer:

x=1+\sqrt{5}, 1-\sqrt{5}

Step-by-step explanation:

  1. x^{2} -2x-4=0
  2. (x-1)^{2} -1-4=0
  3. (x-1)^{2} -5=0
  4. (x-1)^{2} =5
  5. x-1=\sqrt{5} ,-\sqrt{5}
  6. x=1+\sqrt{5} , 1-\sqrt{5}

<u>FINAL ANSWER</u>

x=1+\sqrt{5} , 1-\sqrt{5}

<u><em>In Decimal Form (Rounded to 3 significant figures)</em></u>

<em>x≈-1.24, 3.24</em>

6 0
4 years ago
Read 2 more answers
PLZ HEEEELP!!!!! 10 POINTS!!!!
katrin2010 [14]

Answer:

Step-by-step explanation:

Part a

We need two inequalities, one for time worked at each job and the other

for amounts of money earned.

time:  Let b and c represent the time (number of hours) worked at babysitting and landscaping respectively.  Then b + c ≤ 20 hrs/wk

earnings:  Let ($3/hr)(b) represents the amount of money earned babysitting for b hour.  Let  ($7/hr)(c) represent the money earned working at landscaping.  These amounts are <em>per week</em>.  The appropriate inequality is  ($3/hr)(b) +  ($7/hr)(c) ≥ $84 per week.  The other inequality is

b + c ≤ 20 hrs/wk.

Part b:

As before, b + c ≤ 20 hrs/wk.  What happens if Chet spends all his 20 hours babysitting?  To answer this, set c = 0 (no landscaping hours).  Then b ≤ 20 hours.  At $3/hr, he could earn only $60 and have no time left for landscaping.  Not good.

Let's experiment:  suppose he works 15 hours babysitting and 5 hours landscaping.  His earnings would be $45 + $35, or $80.  Still not enough; he wants to earn $84 total.    Let's redistribute his time and try again:  suppose he works 14 hours babysitting and 6 hours landscaping; his earnings would be $42 + $42, or $84.  So {b = 14 hours and c + 6 hours} is a solution.  As we continue to reduce the number of hours Chet works babysitting and correspondingly increase those he works landscaping, his earnings will go up, beyond $84.

Here's a table that summarizes this:

babysitting          landscaping    total amount

  hours                   hours               earned

      15                          5                      $60 (not acceptable)

       14                         6                       $84 (borderline acceptable)

       12                          8                       $36 + $42 = $78 (great)

        6                          14                       $116 (greater still)

         2                          18                     $132

          1                           19                      $134

          0                          20                      $140

Summary:  Chet can work anywhere from 0 to 14 hours babysitting and expect to earn $84 or more.

4 0
3 years ago
Determine the slope of each line.
faust18 [17]
(2,-2)(5,7)

7-(-2)= 9
5-2= 3
9/3= 3

slope = 3

(you could also calculate the slope by just counting up how many units it goes up/down when you pick a point from the x-axis and move left/right. basically counting the rise over run)
7 0
4 years ago
Dan multiplied 1,563 by 4 and got the incorrect product of 2,252. Find the correct product and explain what Dan did wrong. Pleas
Morgarella [4.7K]

Answer:

The correct product is 6,252.

I don't know what Dan did wrong lol

8 0
3 years ago
Reading proficiency: An educator wants to construct a 99.5% confidence interval for the proportion of elementary school children
Shkiper50 [21]

Answer:

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error of the interval is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this problem, we have that:

p = 0.69

99.5% confidence level

So \alpha = 0.005, z is the value of Z that has a pvalue of 1 - \frac{0.005}{2} = 0.9975, so Z = 2.81.

Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?

This is n when M = 0.07. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.07 = 2.81\sqrt{\frac{0.69*0.31}{n}}

0.07\sqrt{n} = 1.2996

\sqrt{n} = \frac{1.2996}{0.07}

\sqrt{n} = 18.5658

(\sqrt{n})^{2} = (18.5658)^{2}

n = 345

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

4 0
3 years ago
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