Answer:
The probability that none of the meals will exceed the cost covered by your company is 0.2637.
Step-by-step explanation:
A hyper-geometric distribution is used to define the probability distribution of <em>k</em> success in <em>n</em> samples drawn from a population of size <em>N</em> which include <em>K</em> success. Every draw is either a success of failure.
The random variable <em>X</em> = number of meals that will exceed the cost covered by the company.
The random variable <em>X</em> follows a hyper-geometric distribution.
The information provided is:
N = 15
K = 3
n = 5
k = 0
The probability mass function of a hyper-geometric distribution is:
![P(X=k)=\frac{{K\choose k}{N-K\choose n-k}}{{N\choose n}}](https://tex.z-dn.net/?f=P%28X%3Dk%29%3D%5Cfrac%7B%7BK%5Cchoose%20k%7D%7BN-K%5Cchoose%20n-k%7D%7D%7B%7BN%5Cchoose%20n%7D%7D)
Compute the probability that none of the meals will exceed the cost covered by your company as follows:
![P(X=0)=\frac{{3\choose 0}{15-3\choose 5-0}}{{15\choose 5}}=\frac{1\times 792}{3003}=0.2637](https://tex.z-dn.net/?f=P%28X%3D0%29%3D%5Cfrac%7B%7B3%5Cchoose%200%7D%7B15-3%5Cchoose%205-0%7D%7D%7B%7B15%5Cchoose%205%7D%7D%3D%5Cfrac%7B1%5Ctimes%20792%7D%7B3003%7D%3D0.2637)
Thus, the probability that none of the meals will exceed the cost covered by your company is 0.2637.
Answer:
Step-by-step explanation:
6
cause you take 48/8 equals 6
hope this heps:)
The answer is 5.13 in²
Step 1. Calculate the diameter of the circle (d).
Step 2. Calculate the radius of the circle (r).
Step 3. Calculate the area of the circle (A1).
Step 4. Calculate the area of the square (A2).
Step 5. Calculate the difference between two areas (A1 - A2) and divide it by 4 (because there are total 4 segments) to get <span>the area of one segment formed by a square with sides of 6" inscribed in a circle.
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Step 1:
The diameter (d) of the circle is actually the diagonal (D) of the square inscribed in the circle. The diagonal (D) of the square with side a is:
D = a√2 (ratio of 1:1:√2 means side a : side a : diagonal D = 1 : 1 : √2)
If a = 6 in, then D = 6√2 in.
d = D = 6√2 in
Step 2.
The radius (r) of the circle is half of its diameter (d):
r = d/2 = 6√2 / 2 = 3√2 in
Step 3.
The area of the circle (A1) is:
A = π * r²
A = 3.14 * (3√2)² = 3.14 * 3² * (√2)² = 3.14 * 9 * 2 = 56.52 in²
Step 4.
The area of the square (A2) is:
A2 = a²
A2 = 6² = 36 in²
Step 5:
(A1 - A2)/4 = (56.52 - 36)/4 = 20.52/4 = 5.13 in²