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sertanlavr [38]

3 years ago

9

a baseball team has home games on Friday and Saturday. the two games together earn 3979.00 for the team. Fridays game generates

781.00 less then Saturdays game. how much money was taken in at each game?

1 answer:

mojhsa [17]3 years ago

8 0

3979.00-781.00= 3198.00 is how much money was taken in at each game

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Romashka-Z-Leto [24]

Step-by-step explanation:

4 H (Hundreds)

5 T(tens)

9 ones

3x3= 9

50x3= 150

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add 300+150+9= 459

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Set A contains all integers from 50 to 100 inclusive, Set B contains all integers from 69 to 138 exclusive. How many integers ar

mario62 [17]

Answer: C. 31

Explanation:
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Notice that Set B and Set A have an overlap from 70 to 100. So that is 31 elements in total. Hence the set A intersect B is [70, 71, 72, … , 99, 100] which is 31 elements.

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2 years ago

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umka2103 [35]

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7 0

3 years ago

Read 2 more answers

What will the expression below simplify to after combining like terms? *<br> 4 + 6x + 3 + 4x

cupoosta [38]

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3 years ago

Find the solution of the given initial value problem in explicit form. y' = (1 – 11x)y?, y(0) = -1 Enclose numerators and denomi

Tanya [424]

Answer:

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Step-by-step explanation:

This is a separable equation. First divide both sides by y:

$\frac{dy(x)}{\frac{dx}{y(x)} } =-11x+1\\\frac{dy}{y}=(-11x+1)dx$

Integrate both sides:

$\int\ \frac{dy}{y} \ =\int\ (-11x+1) \, dx$

$log(y)=-(\frac{11*x}{2} )+x+ c_1$

Solve for y taking exp to both sides:

$y(x)=c_1*e^{x-(\frac{11*x^{2} }{2}) }$

Where $c_1$ is an arbitrary constant

Evaluating the initial condition:

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$c_1*e^{0} =-1\\c_1*1=-1\\c_1=-1$

Finally, replacing $c_1$ in the differential equation solution:

$y(x)=-e^{x-(\frac{11*x^{2} }{2}) }$

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3 years ago