The length, l, is 2 more than twice the width, w. l= 2w+2 (2 more than twice w) In a rectangle, we have two of the same lengths and two of the same widths. 2l+2w=34 Divide by 2 on each side. l+w=17 We remember that l is 2w+2 Substituting that back in we get, 2w+2+w=17 3w+2=17 3w=15 w=5 We sub w back into l+w=17 l+5=17 l=12 The dimensions are 5 by 12 inches.
Let, the length of the rectangular picture frame be "x" the width of the rectangular picture frame be "y" Then, according to the question, x = 2 + 2y ........................................................equation (1)
Perimeter = 34 inches
Now, We have, perimeter of the rectangular = 2 ( length + width) 34 = 2 ( x + y) 34 = 2 ( 2 + 2y + y) 34 = 2 (2 + 3y) 34 = 4 + 6y 34 - 4 = 6y 30 = 6y 30 / 6 = y 5 = y Now, taking equation (1) x = 2 + 2y substituting the value of "y" , we get, x = 2 + 2(5) x = 2 + 10 x = 12
So, the dimensions of the rectangular frame are 12 inches and 5 inches
300=x+1.9x I got this by dividing the problem into two parts x[the speed of the first half] plus 1.9x [the speed of the second half increased by 1.9] both of those together should give you 300. I went further and solved this...If you placed 103.5 into this problem for x you should get 300.15!
