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kati45 [8]
3 years ago
14

A large university accepts 70​% of the students who apply. Of the students the university​ accepts, 45​% actually enroll. If 30

comma 000 students​ apply, how many actually​ enroll?
Mathematics
1 answer:
uysha [10]3 years ago
4 0

Answer: the number of students that actually enroll is 9450

Step-by-step explanation:

The large university accepts 70​% of the students who apply. If 30 comma 000 students​ apply, it means that the total number of students that applied is 30000 and the number of students accepted would be 70/100 × 30000 = 21000

Of the students that the university​ accepts, 45​% actually enroll. This means that the number of students that enrolled would be

45/100 × 21000 = 0.45×21000

= 9450

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lisov135 [29]

   ln 5
e              =    ?
                                    x
Keep in mind that y=e     and y = ln x are inverse functions of one another.
  ln 5
e       ,  we can drop both the "e" and the "ln 5."  We are left with 5 (answer).
                                                                                        ln 5
Alternatively, we could take the ln of both sides of y = e

which will result in ln y = (ln 5) ln e.  Note that ln e = 1 (these two functions are inverses of one another).

Then we are left with ln y = ln 5.  Dropping the "ln" operator from both sides,

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spayn [35]

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zubka84 [21]

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