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kati45 [8]
4 years ago
14

A large university accepts 70​% of the students who apply. Of the students the university​ accepts, 45​% actually enroll. If 30

comma 000 students​ apply, how many actually​ enroll?
Mathematics
1 answer:
uysha [10]4 years ago
4 0

Answer: the number of students that actually enroll is 9450

Step-by-step explanation:

The large university accepts 70​% of the students who apply. If 30 comma 000 students​ apply, it means that the total number of students that applied is 30000 and the number of students accepted would be 70/100 × 30000 = 21000

Of the students that the university​ accepts, 45​% actually enroll. This means that the number of students that enrolled would be

45/100 × 21000 = 0.45×21000

= 9450

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Step-by-step explanation:

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Similarly: between the y-components:  1 - (-6) = 7

Apply the Pythagorean Theorem:  9^2 + 7^2 = d^2, where d is the desired distance:

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Answer:

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Step-by-step explanation:

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3 years ago
<img src="https://tex.z-dn.net/?f=z%5E%7B7%7D%3D128i" id="TexFormula1" title="z^{7}=128i" alt="z^{7}=128i" align="absmiddle" cla
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If <em>z</em> ⁷ = 128<em>i</em>, then there are 7 complex numbers <em>z</em> that satisfy this equation.

z^7 = 128i = 2^7i = 2^7e^{i\frac\pi2}

\implies z=\sqrt[7]{2^7} e^{i\frac17\left(\frac\pi2+2n\pi\right)}

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\displaystyle\implies z = 2 \left(\cos\left(\frac\pi{14}+\frac{2n\pi}7\right)+i\sin\left(\frac\pi{14}+\frac{2n\pi}7\right)\right)

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i believe it is C but do not trust me on this :p

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4 years ago
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