Answer:
Chain referral sampling
Step-by-step explanation:
Chain referral sampling is also known as snowball sampling. In this form of sampling, the samples are collected from the referrals given by the existing samples. The samples are collected and the research is conducted respectively. This method is used in the business marketing also. The places where the people are not known by the company, the method of chain referrals are made and the samples are collected.
Answer: Solve for Y
y = -16x - 38
And then y intercept is
(0, -38)
Step-by-step explanation:
Answer:
C)16
Step-by-step explanation:
assuming the rhombus is named ABCD and E is where the diagonals meet.
Rhombus is a quadrilateral in which
- All sides are equal
- Opposite internal angles are equal
- Diagonals bisect each other at right angles
As rhombus is ABCD , AC is a diagonal which is bisected by E (According to the properties of Rhombus)
therefore AC will be twice of AE which is given to be 8
⇒ Answer is 16
Answer:

Step-by-step explanation:
<u>Linear Combination Of Vectors
</u>
One vector
is a linear combination of
and
if there are two scalars
such as

In our case, all the vectors are given in
but there are only two possible components for the linear combination. This indicates that only two conditions can be used to determine both scalars, and the other condition must be satisfied once the scalars are found.
We have

We set the equation

Multiplying both scalars by the vectors

Equating each coordinate, we get



Adding the first and the third equations:


Replacing in the first equation



We must test if those values make the second equation become an identity

The second equation complies with the values of
and
, so the solution is

Answer:
12 of them
Step-by-step explanation:
2:4
4:8
6:12