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telo118 [61]
3 years ago
13

2x+3y=19 // 6x+2y=22​

Mathematics
2 answers:
zvonat [6]3 years ago
7 0

Answer:

(2, 5 )

Step-by-step explanation:

Given the 2 equations

2x + 3y = 19 → (1)

6x + 2y = 22 → (2)

Multiplying (1) by - 3 and adding to (2) will eliminate the x- term

- 6x - 9y = - 57 → (3)

Add (2) and (3) term by term to eliminate x

0 - 7y = - 35

- 7y = - 35 ( divide both sides by - 7 )

y = 5

Substitute y = 5 into either of the 2 equations and solve for x

Substituting into (1)

2x + 3(5) = 19

2x + 15 = 19 ( subtract 15 from both sides )

2x = 4 ( divide both sides by 2 )

x = 2

solution is (2, 5 )

Nuetrik [128]3 years ago
4 0

Answer:

x=2\\y=5

Step-by-step explanation:

Multiply both sides of the equation by a coefficient:  \left \{ {{3(2x+3y)=19x3} \atop {6x+2y=22}} \right.

Apply Multiplicative Distribution Law: \left \{ {{6x+9y=19x3} \atop {6x+2y=22}} \right.

Calculate the first two terms: \left \{ {{6x+9y=57} \atop {6x+2y=22}} \right.

Subtract the two equations: 6x+9y-(6x+2y)=57-22

Remove parentheses: 6x+9y-6x-2y=57-22

Cancel the unknown variables: 9y-2y=57-22

Combine like terms: 7y=57-22

Calculate the sum or difference: 7y=35

Reduce the greatest common factor on both sides of the equation: y=5

Substitute one unknown quantity into the elimination: 6x+9x5=57

Reduce the greatest common factor on both sides of the equation: 2x+3x5=19

Rearrange unknown terms to the left side of the equation: 2x=19-3·5

Calculate the product or quotient: 2x=19-15

Calculate the sum or difference: 2x=4

Reduce the greatest common factor on both sides of the equation: x=2

Write the solution set of the equations: \left \{ {{x=2} \atop {y=5}} \right.

Answer: \left \{ {{x=2} \atop {y=5}} \right.

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If SU bisects TSV, then TSU = USV
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Answer:

Part A) The distance between Whitney's house and Anh's house is 6.5 miles.

Part B) The total distance traveled by Whitney during the trip was 9.5 miles.

Step-by-step explanation:

Part A)

Notice that during Whitney's journey to Anh's house, her velocity was negative for some time. So, Whitney was travelling backwards. Hence, the total distance Whitney traveled will be greater than the actual distance from Whitney's house to Anh's.

So, instead, we can calculate Whitney's total displacement. Total displacement is given by:

\displaystyle \text{Displacement}=\int_a^bv(t)\, dt

Where <em>v(t)</em> is the velocity function.

So, the displacement of Whitney when she traveled from her house to Anh's house will be:

\displaystyle \text{Displacement}=\int_0^{24}v(t)\, dt

To calculate the integral, we can split it off at <em>t</em> = 11, <em>t</em> = 16, and <em>t</em> = 24.

The three regions represent three geometric figures, which we can use to calculate the area and then find the integral. Rewriting:

\displaystyle \text{Displacement}=\int_0^{11}v(t)\, dt+\int_{11}^{16}v(t)\, dt+\int_{16}^{24}v(t)\, dt

Now, we can calculate the area of each figure.

The first figure is a trapezoid with a height of 0.8 and two bases of 11 and 3. So, its area is:

\displaystyle A_1=\frac{1}{2}(0.8)(11+3)=5.6\text{ miles}

The second figure is a triangle with a height of 0.6 and a base of 5. So, its area is:

\displaystyle A_2=\frac{1}{2}(0.6)(5)=1.5\text{ miles}

Lastly, the third figure is another triangle will a height of 0.6 and a base of 8. So, its area is:

\displaystyle A_3=\frac{1}{2}(0.6)(8)=2.4\text{ miles}

However, notice that the second figure is below the <em>x</em>-axis. During that interval, Whitney was traveling backwards. Hence, we will subtract the second area from the rest of the areas.

Then the displacement will be:

\displaystyle \text{Displacement}=5.6-1.5+2.4=6.5\text{ miles}

So, the distance between Whitney's house and Anh's house is 6.5 miles.

Part B)

The total distance differs from displacement in that it includes all the distances in both directions. It is given by:

\displaystyle \text{Distance}=\int_a^b|v(t)|\, dt

In other words, all of our values are now positive. We will utilize the same strategy:

\displaystyle \text{Distance}=\int_0^{11}|v(t)|\, dt+\int_{11}^{16}|v(t)|\, dt+\int_{16}^{24}|v(t)|\, dt

Substitute. The only difference is that we will add 1.5 instead of subtracting it. So:

\displaystyle \text{Distance} =5.6+1.5+2.4=9.5

Therefore, in this instance, Whitney traveled a total of 9.5 miles to get to Anh's house.

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Nimfa-mama [501]

The answer is C because AO and BO are equal. And with AO being three times the length of CO, BO should be the length of DO

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