Question

Cars Benito wants to buy a car. He is considering two different models.Model A is 7 1/8 ft wide. Model B is 93 in. wide. Part a. express the width of each car in ft using a decimal. Part b. which car is wider?

Answer 1

Model A is 7.125 ft wide.  Model B is 93/12 = 7  $\frac{9}{12}$ or 7 $\frac{3}{4}$  which can be written as the decimal 7.75

To compare we add a zero to make them the same length

7.125 < 7.750  so Model B is wider by .625ft  (or 5/8 of a foot)

Answer 2

Answer:

a). Model A = 7.125 ft

Model B = 7.75 ft

b). Car B is wider than Car A.

Step-by-step explanation:

a). Model A of the car is $7\frac{1}{8}$ ft wide.

Model B is 93 inches wide.

Since 12 inches = 1 foot

      So, 1 inch  = $\frac{1}{12}$ foot

Therefore, 93 inches = $\frac{93}{12}$ feet

                                   = $\frac{31}{4}$ feet or $7\frac{3}{4}$ feet

Length of the model A =  $7\frac{1}{8}$ ft = 7.125 ft

Length of the model B =  $7\frac{3}{4}$ ft = 7.75 ft

b). Now we have to compare both the models having measures $7\frac{1}{8}$ ft and $7\frac{3}{4}$ feet respectively.

As we ave seen in part (a), model B is more wider than model B.

Therefore, car B will be more wider.