HELPPPP NOW ASAP A dartboard has 20 equally divided wedges, and you are awarded the number of points in the section your dart la
nds in. If you are equally likely to land in any wedge, what is the probability you will score 21 points?
1 answer:
Answer:
0.
Step-by-step explanation:
It is given that a dartboard has 20 equally divided wedges, and we are awarded the number of points in the section your dart lands in.
It means you can score from 1 to 20 in one trial.
We need to find the probability we will score 21 points.
Number of wedges with mark 21 = 0
Total number of wedges = 20
Therefore, the required probability is 0. It means it is an impossible event.
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Answer:
x = -14
Step-by-step explanation:
Look at the image attatched. I have labeled the angles for better explanation.
We know that angle 1 is 54 degrees as is rests on a straight line with its adjacent angle at 126 degrees. This means that angle 1 would be 180 - 126 degrees, or 54 degrees. We also know that angle 1 and 3 must be congruent as the sides of the triangle opposite those angles are congruent as well. This means that both those angles are 54 degrees. Since the sum of all angles in a triangle must equal 180 degrees, we can get that angle 4 is 180 - (2*54) degrees, or 72. Since angle two and angle 4 both lie on a straight line, they must add up to 180 degrees. This means that the value of angle 2 would be 180 - 72, or 108 degrees. Since angle 2 is also equal to x+122, we get the equation:
108 = x + 122.
We then solve this by getting:
x = 108 - 122
which gives us the answer of
x = -14
