HELPPPP NOW ASAP A dartboard has 20 equally divided wedges, and you are awarded the number of points in the section your dart la
nds in. If you are equally likely to land in any wedge, what is the probability you will score 21 points?
1 answer:
Answer:
0.
Step-by-step explanation:
It is given that a dartboard has 20 equally divided wedges, and we are awarded the number of points in the section your dart lands in.
It means you can score from 1 to 20 in one trial.
We need to find the probability we will score 21 points.
Number of wedges with mark 21 = 0
Total number of wedges = 20
Therefore, the required probability is 0. It means it is an impossible event.
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Answer:
~8.66cm
Step-by-step explanation:
The length of a diagonal of a rectangular of sides a and b is
in a cube, we can start by computing the diagonal of a rectangular side/wall containing A and then the diagonal of the rectangle formed by that diagonal and the edge leading to A. If the cube has sides a, b and c, we infer that the length is:
Using this reasoning, we can prove that in a n-dimensional space, the length of the longest diagonal of a hypercube of edge lengths is
So the solution here is
Answer:
The 99% confidence interval is (3.0493, 3.4907).
We are 99% sure that the true mean of the students Perry score is in the above interval.
Step-by-step explanation:
Our sample size is 21.
The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So
.
Then, we need to subtract one by the confidence level and divide by 2. So:
Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have
Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So
Now, we multiply T and s
Then
The lower end of the interval is the mean subtracted by M. So:
The upper end of the interval is the mean added to M. So:
The 99% confidence interval is (3.0493, 3.4907).
Interpretation:
We are 99% sure that the true mean of the students Perry score is in the above interval.