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Kay [80]
3 years ago
13

HELPPPP NOW ASAP A dartboard has 20 equally divided wedges, and you are awarded the number of points in the section your dart la

nds in. If you are equally likely to land in any wedge, what is the probability you will score 21 points?

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
8 0

Answer:

0.

Step-by-step explanation:

It is given that a dartboard has 20 equally divided wedges, and we are awarded the number of points in the section your dart lands in.  

It means you can score from 1 to 20 in one trial.

We need to find the probability we will score 21 points.

Number of wedges with mark 21 = 0

Total number of wedges = 20

\text{Probability}=\dfrac{\text{Number of wedges with mark 21}}{\text{Total number of wedges}}

\text{Probability}=\dfrac{0}{20}

\text{Probability}=0

Therefore, the required probability is 0. It means it is an impossible event.

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Step-by-step explanation:

2x-3(20-3x)+12

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-7x-48

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TiliK225 [7]

Two eventis are independent if knowledge about the first doesn't change your expectation about the second.

a) Independent: After you know that the first die showed 4, you stille expect all 6 numbers from the second. So, the fact that the first die showed 4 doesn't change your expectation about the second die: it can still show numbers from 1 to 6 with probability 1/6 each.

b) Independent: It's just the same as before. After you know that the first coin landed on heads, you still expect the second coin to land on heads or tails with probability 1/2 each. Knowledge about the first coin changed nothing about your expectation about the second coin.

a) Dependent: In this case, there is a cause-effect relation, so the events are dependent: knowing that a person is short-sighted makes you almost sure that he/she will wear glasses. So, knowledge about being short sighted changed your expectation about wearing glasses.

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What is the range of the function y= e4x?
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Answer:

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Step-by-step explanation:

We need to find the range of y = e^4x

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