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Kay [80]
4 years ago
13

HELPPPP NOW ASAP A dartboard has 20 equally divided wedges, and you are awarded the number of points in the section your dart la

nds in. If you are equally likely to land in any wedge, what is the probability you will score 21 points?

Mathematics
1 answer:
Varvara68 [4.7K]4 years ago
8 0

Answer:

0.

Step-by-step explanation:

It is given that a dartboard has 20 equally divided wedges, and we are awarded the number of points in the section your dart lands in.  

It means you can score from 1 to 20 in one trial.

We need to find the probability we will score 21 points.

Number of wedges with mark 21 = 0

Total number of wedges = 20

\text{Probability}=\dfrac{\text{Number of wedges with mark 21}}{\text{Total number of wedges}}

\text{Probability}=\dfrac{0}{20}

\text{Probability}=0

Therefore, the required probability is 0. It means it is an impossible event.

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Find the discriminant and determine the nature of the roots to the quadratic equation
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№17
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№19
2 x^{2} -4x-5=0 \\  D=-4 ^{2} -4*2*(-5)=16+40=56 \\  \\  x_{1}= \frac{4+ \sqrt{56} }{2*2}  = \frac{4}{4} + \sqrt{ \frac{56}{16} } =1+ \sqrt{3.5}  \\  \\  x_{2} = \frac{4- \sqrt{56} }{2*2} = \frac{4}{4} -  \sqrt{ \frac{56}{16} } =1- \sqrt{3.5} 

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4 years ago
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Answer:

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