Step-by-step explanation:
the line given slope = x coefficient = -5/2
Perpendicular slopes must be opposite reciprocals of each other: m1 * m2 = –1
new slope = 2/5
line equation formula = y = mx+ b
m = slope
y= 2/5x + b
from the point given (-6,0)
x = -6
y = 0
0= -12/5 + b
b = +12/5
line equation =

Answer:
(x, y) = (-1, 6)
Step-by-step explanation:
y = 2x + 8
y = 5 - x
Substituting the second equation into the first equation, we get:
5 - x = 2x + 8
5 = 3x + 8
-3 = 3x
x = -1.
So, y = 5 - (-1).
Simplifying, we get:
y = 6.
The answer to the problem is A
Answer:
The answer is cosx cot²x ⇒ the first answer
Step-by-step explanation:
∵ cot²x = cos²x/sin²x
∵ secx = 1/cosx
∴ cot²x secx - cosx = (cos²x/sin²x)(1/cosx) - cosx
= (cosx/sin²x) - cosx
Take cosx as a common factor
∴ cosx[(1/sin²x) - 1] ⇒ use L.C.M
∴ cosx[1-sin²x/sin²x]
∵ 1 - sin²x = cos²x
∴ cosx(cos²x/sin²x) = cosx cot²x
Although the question is incomplete, I have seen it before.
The equations are:
3a + 6b = 12
-3a + 6b = -12
Adding the equations, we get:
12b = 0
And b = 0