HELPPPP NOW ASAP A dartboard has 20 equally divided wedges, and you are awarded the number of points in the section your dart la
nds in. If you are equally likely to land in any wedge, what is the probability you will score 21 points?
1 answer:
Answer:
0.
Step-by-step explanation:
It is given that a dartboard has 20 equally divided wedges, and we are awarded the number of points in the section your dart lands in.
It means you can score from 1 to 20 in one trial.
We need to find the probability we will score 21 points.
Number of wedges with mark 21 = 0
Total number of wedges = 20
Therefore, the required probability is 0. It means it is an impossible event.
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Answer:
0.0903
Step-by-step explanation:
Given that :
The mean = 1450
The standard deviation = 220
sample mean = 1560
P(X> 1560) = P(Z > 0.5)
P(X> 1560) = 1 - P(Z < 0.5)
From the z tables;
P(X> 1560) = 1 - 0.6915
P(X> 1560) = 0.3085
Let consider the given number of weeks = 52
Mean = np = 52 × 0.3085 = 16.042
The standard deviation =
The standard deviation =
The standard deviation = 3.3306
Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.
Then;
Pr ( Y > 20) = P( z > 20)
From z tables
P(Y > 20) 0.0903