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Mathematics

1 answer:

scoundrel [369]3 years ago

5 0

Answer:

X+Y is greater then or equal to 8

Step-by-step explanation:

In total she wants to sell at least 8 items which implies shes willing to sell more (so greater or equal to) then it's adding X+Y bc those are the items that she is selling

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Nathan took his car in for service and repairs. He had a coupon for 10% off. Original Prices • Labor $218.97 • Parts $303.47 • O

Dmitry_Shevchenko [17]

Answer:

C PLEASE GIVE BRAINLIEST

Step-by-step explanation:

218.97 + 303.47 + 77.78 = $600.22

600.22 x .10 = 60.02 (amount of discount)

600.22 - 60.02 = $540.20 (amount he owes)

Answer is C

7 0

3 years ago

Read 2 more answers

a store has a 20% off sale on pants with this discount, the price of one pair of pants before tax is $15.20. what was the origin

anastassius [24]

Answer:

19$

Step-by-step explanation:

In this problem, we have to apply the rule of three. Also, we must have present that $15.20 is the 80% of the price, because the store offers a 20% of discount. So, if $15.20 is 80%, how much would be the 100%?

Therefore, the original price of the pants is $19.

Remember that we must identified the right proportion to apply the rule of three, in this case, that proportion is the 80% with 15.20, that's the reason or fraction center of the whole operation.

7 0

3 years ago

Find k so that the distance from (–1, 1) to (2, k) is 5 units. k= k= *there are two solutions for 2*

dalvyx [7]

Answer:

k = -3

k =5

Step-by-step explanation:

$d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d = 5\\(-1,1) =(x_1,y_1)\\(2,k)=(x_2,y_2)\\$

$5=\sqrt{\left(2-\left(-1\right)\right)^2+\left(k-1\right)^2}\\\\\mathrm{Square\:both\:sides}:\quad 25=k^2-2k+10\\25=k^2-2k+10\\\\\mathrm{Solve\:}\:25=k^2-2k+10:\\k^2-2k+10=25\\\\\mathrm{Subtract\:}25\mathrm{\:from\:both\:sides}\\k^2-2k+10-25=25-25\\k^2-2k-15=0\\\\\mathrm{Solve\:by\:factoring}\\\\\mathrm{Factor\:}k^2-2k-15:\quad \left(k+3\right)\left(k-5\right)\\\mathrm{Solve\:}\:k+3=0:\quad k=-3\\$