Answer:
I'll setup the problem, then you can do the calculations
Step-by-step explanation:
Perimeter = 2width(W) + 2length (L)
Area = LW
L = 2.5 + 2W
LW = 62.5
substitute L in equation for area
a = 2; b = 2.5; c = 62.5
send a comment if you have a question
Answer:
1. Objective function is a maximum at (16,0), Z = 4x+4y = 4(16) + 4(0) = 64
2. Objective function is at a maximum at (5,3), Z=3x+2y=3(5)+2(3)=21
Step-by-step explanation:
1. Maximize: P = 4x +4y
Subject to: 2x + y ≤ 20
x + 2y ≤ 16
x, y ≥ 0
Plot the constraints and the objective function Z, or P=4x+4y)
Push the objective function to the limit permitted by the feasible region to find the maximum.
Answer: Objective function is a maximum at (16,0),
Z = 4x+4y = 4(16) + 4(0) = 64
2. Maximize P = 3x + 2y
Subject to x + y ≤ 8
2x + y ≤ 13
x ≥ 0, y ≥ 0
Plot the constraints and the objective function Z, or P=3x+2y.
Push the objective function to the limit in the increase + direction permitted by the feasible region to find the maximum intersection.
Answer: Objective function is at a maximum at (5,3),
Z = 3x+2y = 3(5)+2(3) = 21
Answer:
-46
Step-by-step explanation:
We need to find the common difference of this arithmetic sequence:
So, the common difference d = -4. We can now write the equation:
So, the 15th term is -46.
Hope this helps!