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lianna [129]
3 years ago
11

Is 1x^2-2x-15=0 a vertical stretch or compression HURRY PLEASE!!

Mathematics
1 answer:
alexdok [17]3 years ago
5 0

Answer:

NEITHER vertical stretching NOR vertical compression

Step-by-step explanation:

f(x) = 1x^2-2x-15  =  1x^2 - 2x - 15

Because the coefficient of the x^2 term is 1, there is NEITHER vertical stretching NOR vertical compression.

Here f(x) = 1x^2 - 2x - 15 = x^2 - 2x + 1 - 1 - 15  =  (x - 1)^2 - 16

represents a parabola whose vertex is at (1, -16), which opens up, and which has stretching in neither direction (horizontal or vertical).

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Step-by-step explanation:

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We are interested in the x^3y^3 term which represents exactly 3 successes. Since the probability of success and failure are both .5 we should be able to figure this out just using the coefficients of the terms which is  

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