Answer:
-1<x<7
Step-by-step explanation:
We need to solve each inequality and then from the interval of numbers they both have in common (doing this because of the 'and').
x-2<5
Add 2 on both sides:
x<5+2
Simplify:
x<7
These are values of x that are less than 7.
x+7>6
Subtract 7 on both sides:
x>6-7
Simplify:
x>-1
These are values of x greater than -1.
So the values they have in common are the numbers in between -1 and 7.
That is x<7 and x>-1.
You can also write it as -1<x<7.
Maybe you need a graph to convince you more.
○~~~~~~~~~~~~~~~~~~~~~~~~~~~
~~~~~~~~~~~~~~~~~~~~~~~~~○
‐-------------(-1)------------------------(7)-----------------
So where you see both graphs is the solution:
○~~~~~~~~~~~~~~○
‐-------------(-1)------------------------(7)-----------------
Answer:
It is symmetric about x- axis
The graph is not symmetric along the y - axis
It is not symmetric about the origin
Step-by-step explanation:
We can easily know the solution to your problem by graphing the equation
r(θ) = 2*cos (5*θ)
Please, see attached image
The graph is symmetric about the x axis if
r(θ) = r(-θ)
r(θ) = 2*cos (5*θ) = 2*cos (-5*θ) = r(-θ)
Since the cosine is an even function.
It is symmetric about x- axis
The graph is not symmetric along the y - axis, because
r(θ) ≠ r(π-θ)
It is symmetric about the origin if
r(θ) = r(π+θ)
But, since,
r(θ) = 2*cos (5*θ) ≠ 2*cos (5*(θ+π)) = 2*cos (5*θ+5*π)
It is not symmetric about the origin
98 people get $30 per hour, and 11 get an additional $15 per hour. Then the total payroll per hour is
.. $(98*30 +11*15) = $3105
So, the payroll for a 40-hour week is
.. 40*$3105 = $124,200
First, you separate the h variable by subtracting s^2 on both sides of the equation, getting
V - s^2 = sh/2
Then, all you have to do is divide both sides by s/2, so you get
h = 2*(v - s^2)/s as your final answer.
Answer:
The answer is "It has the same domain as the function f(x) = --x".
Step-by-step explanation:
If we consider its parent function that is: y= x
Domain function is: 
The range function is: 
The function has both the same (domain and range).
