Hi, Please help me solve 28

Which is bigger 0.21, 21%

andrew11 [14]

21% is bigger than 0.21

5 0

3 years ago

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Find the value of x in the triangle.

Hatshy [7]

Answer:

Step-by-step explanation:

The sum of measures of angles in triangle is allways 180°

So:

x + 53° + 60° = 180° {subtract 113° from both sides}

x = 67°

3 0

2 years ago

1. Solve for the variable. x - 4.5 = 11.3

polet [3.4K]

Answer:

15.8

Step-by-step explanation:

do 11.3 + 4.5 = 15.8

7 0

3 years ago

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Evaluate the integral of the quotient of the cosine of x and the square root of the quantity 1 plus sine x, dx.

VMariaS [17]

Answer:

∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c.

Step-by-step explanation:

In order to solve this question, it is important to notice that the derivative of the expression (1 + sin(x)) is present in the numerator, which is cos(x). This means that the question can be solved using the u-substitution method.

Let u = 1 + sin(x).

This means du/dx = cos(x). This implies dx = du/cos(x).

Substitute u = 1 + sin(x) and dx = du/cos(x) in the integral.

∫((cos(x)*dx)/(√(1+sin(x)))) = ∫((cos(x)*du)/(cos(x)*√(u))) = ∫((du)/(√(u)))

= ∫(u^(-1/2) * du). Integrating:

(u^(-1/2+1))/(-1/2+1) + c = (u^(1/2))/(1/2) + c = 2u^(1/2) + c = 2√u + c.

Put u = 1 + sin(x). Therefore, 2√(1 + sin(x)) + c. Therefore:

∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c!!!

4 0

3 years ago

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d)An insurance company will only sell its Select policy to people for whom the probability of a stroke in the next 10 years is l

NARA [144]

Answer:

Check the explanation

Step-by-step explanation:

The First action is to enter the data in Excel and then save it as a csv file. Then call the data set in R using your saved path, I have made use of my computer path here in my code. please change it for yours.

Here is the code That you need to use for finding the multiple limear regression model and summary of it.

code:

data=read. csv("C:\\Users\\HP\\Desktop\\chegg. csv")

data

attach(data)

model=lm(Risk~Age+Blood.Pressure+Smoker)

summary(model)

And Here is the output:

Call:

lm(formula = Risk ~ Age + Blood.Pressure + Smoker)

Residuals:

Min 1Q Median 3Q Max

-13.1064 -1.5715 0.4225 3.4855 8.5561

Coefficients:

Estimate Std. Error t value Pr(>|t|)

(Intercept) -91.75950 15.22276 -6.028 1.76e-05 ***

Age 1.07674 0.16596 6.488 7.49e-06 ***

Blood.Pressure 0.25181 0.04523 5.568 4.24e-05 ***

Smoker 8.73987 3.00082 2.912 0.0102 *

---

Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

Residual standard error: 5.757 on 16 degrees of freedom

Multiple R-squared: 0.8735, Adjusted R-squared: 0.8498

F-statistic: 36.82 on 3 and 16 DF, p-value: 2.064e-07

The answer is now written in the notebook which i am uploading..

6 0

3 years ago