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VladimirAG [237]
3 years ago
5

What is 1600+3200 pls

Mathematics
1 answer:
andre [41]3 years ago
7 0

1600+3200 = 4800

Answer: 4800

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Suppose that y varies jointly with w and x and inversely with z and y = 32- when w = 6, x = 20, and z = 3. Write the equation th
natulia [17]
Y directly proportional to WX  and inversely to Z. 

Y=k(WX)/Z
Where k is the constant of proportionality. 
So, the first thing is to find the value of this constant. 

k = YZ/WX
  = (32×3)/(6×20)
  = 96/120
  = 0.8
The <span>equation that models the relationship will be;
Y = 0.8(WX/Z)</span>
3 0
3 years ago
the area of the rectangle 56cm. the length is 2cm more than x and the with is 5cm less than twice x. solve for x. round the near
sattari [20]
(x+2)(2x-5)=56

2x^2-5x+4x-10=56

2x^2-x-10=56

2x^2-x-66=0

2x^2-12x+11x-66=0

2x(x-6)+11(x-6)=0

(2x+11)(x-6)=0, since x is a measurement x>0 so:

x=6cm


7 0
3 years ago
Read 2 more answers
Outcome
Luda [366]

Answer: sorry the answer is not clear.

Step-by-step explanation:

4 0
2 years ago
Pls help will give brainliest
lana [24]

Answer: The answer is B

Step-by-step explanation: 122 >7 (z+8) -5 (6+z). Then switch them, 7 (z+8) -5 (6+z) <122. Expanded:  7 (z+8) -5 (6+z) <122:v 2z+26

2z+26<122, subtract 26 from both sides: 2z+26-26<122-26

Simplify: 2z<96, divide both sides by 2: 2z over 2 < 96 over 2

and finally simplified: Z<48

HOPE THIS HELPED YOU OUT!

IF NOT SORRY!

6 0
3 years ago
The sum of an integer and 7 more than the next consecutive integer is 66. find the integer
Cloud [144]

If the sum of an integer and 7 more than the next consecutive integer is 66 then the integers are 29 and 30.

Given that the sum of an integer and 7 more than the next consecutive integer is 66.

Integer is a number that is written without a fraction component. It can be positive as well as negative.

let the first integer be x.

Consecutive integer will be x+1.

Sum of integer and 7 more than the next consecutive integer is 66.

Sum according to the given information=x+x+1+7

=2x+8

2x+8=66

2x=66-8

2x=58

x=58/2

x=29

Next integer=29+1-30.

Hence if the sum of an integer and 7 more than the next consecutive integer is 66 then the integers are 29 and 30.

Learn more about integers at brainly.com/question/17695139

#SPJ4

8 0
2 years ago
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