Can someone help me solve this 1/2:4=1/3:x

liq [111]

$\text{Hello there!}\\\\\text{Solve for c:}\\\\2(5c -7) = 1\\\\\text{First, distribute the 2}\\\\10c-14=1\\\\\text{Add 14 to both sides}\\\\10c=15\\\\\text{Divide both sides by 10}\\\\c=1.5\\\\\boxed{\text{Answer: c = 1.5 or 3/2}}$

8 0

3 years ago

Use a graphing calculator to find the value of the correlation coefficient r and determine if there is a strong correlation amon

alekssr [168]

Using a calculator, the correlation coefficient is of 0.7649. Since the correlation is greater than 0.6, there is strong correlation.

<h3>What is a correlation coefficient?</h3>

It is an index that measures correlation between two variables, assuming values between -1 and 1.

If it is positive, the relation is positive, that is, they are direct proportional. If it is negative, they are inverse proportional.

If the absolute value of the correlation coefficient is greater than 0.6, the relationship is strong.

Using a calculator, we insert the points (x,y) to find the coefficient. In this problem, the points are given as follows:

(1, 5), (4, 8), (8, 3), (13, 10), (19, 13)

The coefficient is of 0.7649. Since the correlation is greater than 0.6, there is strong correlation.

More can be learned about correlation coefficients at brainly.com/question/25815006

#SPJ1

6 0

1 year ago

Please could you explain this step by step I’m really stuck.

allochka39001 [22]

Answer:

x = -2.5
x = 2

Step-by-step explanation:

Hello!

We can remove the denominators by multiplying everything by it.

Solve:

$\frac{5}{x + 3} + \frac4{x + 2} = 2$
$5 + \frac{4(x + 3)}{x + 2} = 2(x + 3)$
$5 + \frac{4x + 12}{x + 2} = 2x + 6$
$5(x + 2) +4x + 12 = (2x + 6)(x + 2)$
$5x + 10 + 4x + 12 = 2x^2 + 6x + 4x + 12$
$9x + 22 = 2x^2 + 10x + 12$

Let's make one side equal to 0.

$0 = 2x^2 + x - 10$

Solve by factoring, and then the zero product property.

$0 = 2x^2 + x - 10\\$

Multiply 2 and -10. You get -20. Think of two number that multiply to -20, and add to 1. If we think about the standard form of a quadratic, $ax^2 + bx + c$ , think two numbers that equal "ac" and add up to "b".