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vova2212 [387]
3 years ago
5

The first step in the process for facturing the trinonmial x2-5x-36 is to

Mathematics
1 answer:
kakasveta [241]3 years ago
7 0
Set up your parentheses, and put x in the front of both because x is squared. It should look like this: (x     )(x     ). Next, you find notice that one sign must be positive, and one must be negative. Then, you find the factors of 36. 6 and 6, 3 and 12, 1 and 36, 18 and 2, and 9 and 4. You then guess and check with the different signs and factors what will get you back to the trinomial using the FOIL method. When you do this, you should get (x-9)(x+4).
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What is the sign of 39 11/13 + -41 1/13
Radda [10]

Answer:

-1.23076923077

Step-by-step explanation:

7 0
2 years ago
4. (03.03 HC)
Kitty [74]

Answer:

A. yes, the data represents a function because u have no repeating x values. A function cannot have repeating x values...they can have repeating y values, just not the x ones

Step-by-step explanation:

B. table : (8,8)(12,12)(14,16)(16,16)

               look at ur points...when x = 8, y = 8...so the table, when x = 8 has a

               value of 8

relation : f(x) = 8x - 5....when x = 8

             f(8) = 8(8) - 5

             f(8) = 64 - 5

             f(8) = 59....and the relation has a value of 59

Therefore, the relation has a greater value when x = 8 <==

C. f(x) = 8x - 5...when f(x) = 19

    19 = 8x - 5

     19 + 5 = 8x

    24 = 8x

    24/8 = x

    3 = x <==

7 0
3 years ago
Suppose you budgeted $2800 for fuel expenses for the year. How many miles could you drive if gas were $2.70 per gallon and your
Julli [10]

Answer:

29037.036 miles

Step-by-step explanation

There are two possible ways to solve this problem.

The first option starts with the $2800 dollars for the years. You first want to divide this by $2.70, because it will give you the amount of gallons of gas you can buy with that money.

2800/2.70 = 1037.037

This means you can buy 1037.037 gallons of gas in the year. Now you need to convert this to miles by multiplying by the amount of miles per gallon.

1037.037 x 28 = 29037.036 gallons

The second way to look at this is dimensional analysis. If you have learned this, then continue on reading this, but if you haven't I might only confuse you. I only suggest this because it can make it a little easier.

For the dimensional analysis, you need to start with what you are given and move to what you need to know, so you will start with the $2800 dollars and move to gallons. $2.70 per gallon and 28 miles per gallon are your conversion factors.

Set it up like this:

2800 dollars  * \frac{1 gallon}{2.70 dollars} * \frac{28 miles}{1 gallon}  = 29037.036 miles

This allows the equation to be more organized, and you can check your work by canceling the units.

Hope this helps.

3 0
2 years ago
Proof that ur lying.
ozzi

Answer:

HELLOOOO

Step-by-step explanation:

JUST WANTED TO SAY THAT BTS IS THE BEST IN KPOP :)

5 0
2 years ago
Read 2 more answers
The data sets show the years of the coins in two collections. Derek's collection: 1950, 1952, 1908, 1902, 1955, 1954, 1901, 1910
KATRIN_1 [288]

Answer:

Derek's collection :

Mean= 1929

Median= 1930

Range= 54

IQR = 48

MAD= 23.75

Paul's collection:

Mean= 1929

Median= 1929.5

Range= 15

IQR = 6

MAD= 3.5

Step-by-step explanation:

1950, 1952, 1908, 1902, 1955, 1954, 1901, 1910

Mean is given by:

(1950+1952+ 1908+1902+1955+1954+1901+1910)/8

=1929

absolute deviation from mean is:

|1950-1929|= 21

|1952-1929|= 23

|1908-1929|= 21

|1902-1929|= 27

|1955-1929|= 26

|1954-1929|= 25

|1901-1929|= 28

|1910-1929|= 19

from the mean of absolute deviation gives the MAD of the data i.e.

(21+23+21+27+26+25+28+`9)/8

23.75

 

:arrange the given data to get the range and median

   1901   1902    1908   1910    1950  1952    1954   1955

The minimum value is: 1901

Maximum value is: 1955

Range is: Maximum value-minimum value

         Range=1955-1901

Range= 54

median is (1910+1950)/2

1930

   the lower set of data=

  1901   1902    1908   1910

first quartile becomes

1902+1908)/2

Q1=1905

and upper set of data is:

1950  1952    1954   1955

we find the median of the  upper quartile or third quartile is:

1952+1954)/2=1953

Q3-Q1=1953-1905=

IQR=48

 

Paul's collection:

1929, 1935, 1928, 1930, 1925, 1932, 1933, 1920

Mean is given by:

1929+1935+ 1928+ 1930+ 1925+ 1932+1933+1920)/8

1929

absolute deviation from mean is:

|1929-1929|=0

|1935-1929|= 6

|1928-1929|= 1

|1930-1929|= 1

|1925-1929|= 4

|1932-1929|= 3

|1933-1929|= 4

|1920-1929|= 9

Hence, we get:

MAD=0+6+1+1+4+3+4+9/8

28/8

3.5

arrange the data in ascending order we get:

1920   1925   1928   1929   1930   1932   1933   1935  

Minimum value= 1920

Maximum value= 1935

Range=  15 (  1935-1920=15 )

The median is between 1929 and 1930

Hence, Median= 1929.5

Also, lower set of data is:

1920   1925   1928   1929  

the first quartile or upper quartile is

1925+1928/2

1926.5

and the upper set of data is:

1930   1932   1933   1935  

We have

1932+1933)/2

1932.5

IQR is calculated as:

Q3-Q1

6

7 0
3 years ago
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