Answer:
Length = 3 cm
Width = 1 cm
Step-by-step explanation:
Let the length of rectangle be l and width of rectangle be w.
According to problem,
l = 3w {Length of rectangle is equal to triple the width}
And Perimeter,P = 8 cm
Since, P = 2 ( l + w )
or 8 = 2( l + w)
Plug l =3w in the above perimeter equation.
We get:
8 = 2( 3w + w)
8 = 2(4w)
8 = 8w
or w = 1 cm
Then length ,l = 3w =3 * 1 = 3 cm
Hence length of rectangle is 3cm and width of rectangle is 1cm.
Answer:
The ball traveled 116.25 m when it hit the ground for the fifth term
Step-by-step explanation:
This is a geometric progression exercise and what we are asked to look for is the sum of a GP.
The ball was dropped from a height of 60 m. This means that the initial height of the ball is 60 m.
First value, a = 60
Each time it hit the ground, it bounced up 1/2 (half) of the height that it dropped.
This is the common ratio, r = 1/2 = 0.5
The number of terms it hits the ground is the number of terms in the GP.
number of terms, n = 5
The distance traveled by the ball when it hit the ground for the fifth term will be modeled by the equation:
0.55 pence or quid per 25 centimeters as if you multiply it by 4 it would be 2.20 pound because 1 metre is 100 centimeters after i divide 100 by 25 i get 4 which would be 1/4 which i would then multiply 1/4 x 2.2 pound
Answer:
The ancient Babylonians calculated the area of a circle by taking 3 times the square of its radius, which gave a value of pi = 3. The first calculation of π was done by Archimedes of Syracuse (287–212 BC), one of the greatest mathematicians of the ancient world.
