Answer:
z score Perry 
z score Alice 
Alice had better year in comparison with Perry.
Step-by-step explanation:
Consider the provided information.
One year Perry had the lowest ERA of any male pitcher at his school, with an ERA of 3.02. For the males, the mean ERA was 4.206 and the standard deviation was 0.846.
To find z score use the formula.
Here μ=4.206 and σ=0.846
Alice had the lowest ERA of any female pitcher at the school with an ERA of 3.16. For the females, the mean ERA was 4.519 and the standard deviation was 0.789.
Find the z score
where μ=4.519 and σ=0.789
The Perry had an ERA with a z-score is –1.402. The Alice had an ERA with a z-score is –1.722.
It is clear that the z-score value for Perry is greater than the z-score value for Alice. This indicates that Alice had better year in comparison with Perry.
B is the correct answer not totally sure tho hope this helps
Answer:
-2<x<8
see below for graph
Step-by-step explanation:
First, we need to solve the inequality.
Inequality: |x-3|<5
Split into two equations:
x-3<5
x-3>-5 (notice how the sign is flipped when we make the number negative)
let's start with x-3<5
add 3 to both sides
x<8
now
x-3>-5
add 3 to both sides
x>-2
The graph is below
the intersection is the solution.
Notice how I made the maroon line go to the right- which shows that it's greater than (for x>-2) and the silver line go to the left, which shows that it's less than (for x<8)
the equation is -2<x<8
Hope this helps!
The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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If you were to plot the function y=-x+6, both functions meet at the point (4,2)
