First, let's write "the sum of a number and 4" as:
<span>n+4</span>.
Then, "seven times" the sum can be written as:
<span>7<span>(n+4)</span></span>
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This "is 6" or "is equal to 6" and can be written as:
<span>7<span>(n+4)</span>=6</span>
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To solve, first expand the term in parenthesis on the left side of the equation by multiplying each term in the parenthesis by 7
<span><span>(7×n)</span>+<span>(7×4)</span>=6</span>
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<span>7n+28=6</span>
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Next, subtract 28 from each side of the equation to isolate the n term while keeping the equation balanced:
<span>7n+28−28=6−28</span>
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<span>7n+0=−22</span>
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<span>7n=−22</span>
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Now, divide each side of the equation by 7 to solve for n while keeping the equation balanced:
<span><span><span>7n</span>7</span>=−<span>227</span></span>
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<span><span><span>7n</span>7</span>=−<span>227</span></span>
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<span>n=−<span>227</span></span>
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The number is <span>−<span><span>227</span></span></span>
