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3 years ago

What is the solution of the equation? w - 2 = -3

Mathematics

1 answer:

Viktor [21]3 years ago

6 0

I think the answer would be c

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Inverse of A=300e^-0.013t

AnnZ [28]

Answer:

$A^{-1}(t)=-\frac{ln(\frac{t}{300})}{0.013}$

Step-by-step explanation:

we have

$A=300e^{-0.013t}$

Exchange the variables A for t and t for A

$t=300e^{-0.013A}$

Isolate the variable A

$\frac{t}{300}=e^{-0.013A}$

Apply ln (natural logarithm) both sides

$ln(\frac{t}{300})=ln[e^{-0.013A}]$

$ln(\frac{t}{300})=(-0.013A)ln(e)$

Remember that

$ln(e)=1$

$ln(\frac{t}{300})=(-0.013A)$

$A=-\frac{ln(\frac{t}{300})}{0.013}$

Let

$A^{-1}(t)=A$

$A^{-1}(t)=-\frac{ln(\frac{t}{300})}{0.013}$

3 0

3 years ago

the distance from a port huron to the indiana state line is approximately 271 miles (via I-94). express this distance in kilomet

riadik2000 [5.3K]

The distance from a port Huron to the Indiana state line = 271 miles (approx)

We have to express the given distance into kilometers.

Since, 1 mile = 1.61 kilometers.

To convert the unit "miles" to "kilometer", we have to multiply the given miles by 1.61 to get the required kilometers.

Therefore, distance in kilometers = $271 \times 1.61$ kilometers

= 436.3 kilometers.

Therefore, the distance from a port Huron to the Indiana state line in kilometers is 436.3 kilometers.

4 0

4 years ago

Round to the nearest hundredth 9.3959.

Masteriza [31]

Answer:

9.40

Step-by-step explanation:

the 5 makes the 9 go up and since it cant go up, then the 3 goes up and the 9 becomes a 0 so it is 9.40

6 0

4 years ago

Eva and jamir like to bake cookies. Eva baked 24 chocolate chip cookies, and jamir baked p peanut butter cookies. Together they

aivan3 [116]

Answer: 32

Step-by-step explanation:

You have your total of 56 and subtract the amount eva made 24 because the leftover 32 have to have been made by Jamir.

4 0

3 years ago

Order: Anadrol-50 (oxymetholone) 200 mg po daily. The recomnes patient who has bipolar disorder? 3 kg 50 e ste for Is the prescr

VMariaS [17]

Answer:

Yes the ordered dose of 200 mg/d lies within the recommended range of 75 mg/d to 375 mg/d

Step-by-step explanation:

Given:

Ordered dose of Anadrol-50 (oxymetholone) = 200 mg per day

Recommended range = 1-5 mg/kg/d

Weight of the patient = 75 kg

Now,

For the patient weighing 75 kg, the recommended dose will be

Minimum dose will be

= Minimum value of Recommended range × Weight of the patient

= 1 mg/kg/d × 75 kg

= 75 mg/d

and,

the Maximum dose will be

= Maximum value of Recommended range × Weight of the patient

= 5 mg/kg/d × 75 kg

= 375 mg/d

Yes the ordered dose of 200 mg/d lies within the recommended range of 75 mg/d to 375 mg/d

4 0

4 years ago