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sladkih [1.3K]
3 years ago
5

What is the value of the digit 5 in the number 6,582.37 times the value of the digit 5 in 1,284.95

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
5 0
Answer:

25

Explanation:

In the first number 5 has a value of 500 and on the second one 5 has a value of 0.05 so 500 x 0.05 = 25
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2 u + 12 &lt; 23<br> 0,1 d + 8 &gt; 0<br> 3 - 4 r &gt; 7<br> 13 &lt; 2 z + 3<br> 6 ≥ 9 - 0, 15 i
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Answer:

Part 1) u< 5.5  

Part 2) d > -80

Part 3) r < -1

Part 4) z>5

Part 5) i\geq 20

Step-by-step explanation:

<u><em>The question is</em></u>

Solve each inequality for the indicated variable

Part 1) we have

2u+12

subtract 12 both sides

2u< 23-12\\2u

Divide by 2 both sides

u< 5.5

The solution is the interval (-∞,5.5)

In a number line the solution is the shaded area at left of u=5.5 (open circle)

The number 5.5 is not included in the solution

Part 2) we have

0.1d+8 >0

subtract 8 both sides

0.1d > -8

Divide by 0.1 both sides

d > -80

The solution is the interval (-80,∞)

In a number line the solution is the shaded area at right of d=-80 (open circle)

The number -80 is not included in the solution

Part 3) we have

3-4r> 7

Subtract 3 both sides

-4r>7-3\\-4r>4

Divide by -4 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

r < -1

The solution is the interval (-∞,-1)

In a number line the solution is the shaded area at left of r=-1.1 (open circle)

The number -1.1 is not included in the solution

Part 4) we have

13< 2z+3

Subtract 3 both sides

13-3

Divide by 2 both sides

5

Rewrite

z>5

The solution is the interval (5,∞)

In a number line the solution is the shaded area at right of z=5 (open circle)

The number 5 is not included in the solution

Part 5) we have

6\geq 9-0.15i

Subtract 9 both sides

6-9\geq -0.15i\\-3\geq -0.15i

Divide by -0.15 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

20\leq i

Rewrite

i\geq 20

The solution is the interval [20,∞)

In a number line the solution is the shaded area at right of i=20 (closed circle)

The number 20 is included in the solution

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