Theyre all labeled correctly, what exactly is the question?
Answer:
x=(7,0),(-1,0) y=(0,-7)
Step-by-step explanation:
The problem deals with fractions comparison, lets do it:
21/30 > 2/3
we begin solving:
21 > (2/3)*30
21 > 2*10
<span>21 > 20
</span>therefore the proposed inequality is true, <span>21/30 > 2/3
You can solve as well getting same denominator for both fractions and comparing directly, in this case we need to get 2/3 to be divided by 30:
2/3 = (10/10)(2/3) = 20/30
So we have:
</span><span>21/30 > 2/3
</span>which is equal to:
<span>21/30 > 20/30
</span>and we compare directly because both fractions are divided by the same number, and we can see that the inequality is true.
You have to find the discriminat b^2 -4ac
If it is > 0, the function has two real solutions
if it is = 0, the function has one real solution
if it is <0, the function has no real solution
6^2 - 4(7)(3) = 36 - 84 = - 48
Answer c. no solution
Pretty sure it’s 5x^2 - 2x
