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Anna35 [415]
3 years ago
9

If a and b are supplementary and m a = 37°45', then m b = ______. 142°55' 52°15’ 52°55’ 142°15'

Mathematics
2 answers:
MariettaO [177]3 years ago
4 0
A + b = 180° = 179° 60';
We have a = 37°45';
Then b = 179° 60' -  37°45' = 142°15';
The last answer is the correct answer!
bonufazy [111]3 years ago
3 0

Answer:

If ∠A and ∠B are supplementary and m∠A = 37°45', then m∠B = ______.  

142°55'

52°15’

52°55’

142°15'

Step-by-step explanation:

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Refer to the table below if needed.
elena-14-01-66 [18.8K]

A quadrant is the area that is divided into the x and y axes

The quadrants in which tan \theta and cot \theta are positive are I and III

<h3>How to determine the quadrants</h3>

The tangent of an angle is calculated as:

\tan(\theta) = \frac{sin(\theta)}{\cos(\theta)}

While the cotangent of the angle is calculated as:

\cot(\theta) = \frac{cos(\theta)}{\sin(\theta)}

The above equations mean that:

For the tangent and cotangent of an angle to be positive, then the sine and the cosine of the angle must have the same sign.

  • In the first quadrant, the sine and the cosine angles are positive.
  • In the third quadrant, the sine and the cosine angles are negative.

Hence, the quadrants in which tan \theta and cot \theta are positive are I and III

Read more about trigonometry ratios at:

brainly.com/question/8120556

7 0
3 years ago
"A student made the following chart to prove that AB2 + BC2 = AC2.
katovenus [111]

Step 3 has an error.

Step-by-step explanation:

Similarity-criteria of triangles:

1. All the corresponding angles of two triangles should be equal.

2. The ratio between the corresponding sides of two triangles should be equal.

In \triangle ABC and \triangle BDC  

\angle BAC = \angle DBC \\\angle ACB = \angle BCD

All the angles of triangle are equal.

∴\triangle ABC \sim \triangle BDC

Since, \triangle ABC \sim \triangle BDC

\frac{AC}{BC}=\frac{AC}{DC}

BC^{2}=AC \times DC

In \triangle ABC and \triangle BDA,

\fbox{\begin\\ \angle ABC= \angle BDA = 90^{\circ}\end{minispace}}

\fbox{\begin \\\angle BAC = \angle BAD\\\end{minispace}}

\angle ACB = \angle ABD

All the angles of triangle are equal.

∴\fbox{\begin\triangle ABC \sim \triangle BDA \end{minispace}}

∵\triangle ABC \sim \triangle BDA  

\frac{AC}{AB}=\frac{AB}{AD}

AB^{2}=AC \times AD

Now, AB^{2}+BC^{2} can be simplified as,

AB^{2}+BC^{2}=AC \times AD+AC \times DC\\AB^{2}+BC^{2}=AC(AD+DC)\\AB^{2}+BC^{2}=AC(AC)\\AB^{2}+BC^{2}=AC^{2}

Learn more:

1. Find the height of the triangle?

brainly.com/question/12989306

2. Which undefined term is needed to define an angle? brainly.com/question/3717797

3. Look at the figure, which trigonometric ratio should you use to find x? brainly.com/question/9880052

Answer Details

Grade: Junior High School

Subject: Mathematics

Chapter: Triangle

Keywords: triangle, similar, similarity, ratio of sides, right triangle, similar triangle, ratio of sides, equal angles, square of hypotenuse, sum, square of legs, sum of square of legs

8 0
3 years ago
HELP asap what is the answer for this
Anestetic [448]

Answer:

4

Step-by-step explanation:

It's a right angle so that means in total it is 90. 90-50=40. You would then set up an equation of 8y+8=40. 40-8=32. You would then have 8y=32. From there you divide 32 by 8 to get 4. y=4

6 0
3 years ago
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