Which polynomials are in standard form? x2 + 3x + 2 q3 – 15q + 12q2 – 16 4a + a2 + a – 2 3x4 + 4x3 – 3x2 – 1 3t3 + 3t2 + 2t 14 +
2 answers:
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Answer:
The answer is below
Step-by-step explanation:
We need to prove that:
(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.
Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.
Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A