Which polynomials are in standard form? x2 + 3x + 2 q3 – 15q + 12q2 – 16 4a + a2 + a – 2 3x4 + 4x3 – 3x2 – 1 3t3 + 3t2 + 2t 14 +
2 answers:
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Answer:
Where "h" is the height of the building.
Step-by-step explanation:
For this exercise it is important to read and analize carefully the information provided.
According to the data given in the exercise, the height of each floor the arquitect is designing is 12 feet.
You want to know the number of floors of 12 feet tall that building can have for a given building height.
Then, you can let "h" represents the height of the building. This will be the variable in the expression.
In order to find the number of those floors that the building can have for "h", you need divide this height by the height of each floor.
Therefore, you can determine that the expression asked in the exercise is the following:
Where "h" is the height of the building.
we want to find the range of
Notice that Whatever value v can possibly produce, that is the Range of v, becomes the range of u.
Then whatever u produces for these values, is the range of u(v(x))
So, first find range of v: clearly the domain of v is R-{0}, as v(0) makes no sense.
We check what values c can v produce:
this means that any c (for now) can be produced... it is enough to let x=1/c
this also means that c cannot be equal to 0 as 1/c makes no sense if c=0.
Thus the range of v is R-{0},
Now we check the range of u(v(x)) for v(x)∈R-{0},
assume we want to produce a value c, so:
since the left side is always positive or 0, for x=0, the right hand side expression must also be positive or zero, which means c-3 must be negative or 0,
thus c-3≤0; c≤3. Here recall that x in u(x) cannot be 0, so c<3.
Answer: The range of u(v(x)) is (-infinity, 3)