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yuradex [85]
3 years ago
14

Factor completely w^4-2401

Mathematics
2 answers:
Verdich [7]3 years ago
6 0
w^4-2401=(w^2)^2-49^2=(w^2-49)(w^2+49)=(w^2-7^2)(w^2+49)\\\\=(w-7)(w+7)(w^2+49)\\\\------------------------------\\\\a^2-b^2=(a-b)(a+b)
FromTheMoon [43]3 years ago
5 0
w^4-2.401 \\ =(w^2+49)(w^2-49) \\ =(w^2+49)(w-7)(w+7)
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aev [14]

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5 0
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Read 2 more answers
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