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yuradex [85]
3 years ago
14

Factor completely w^4-2401

Mathematics
2 answers:
Verdich [7]3 years ago
6 0
w^4-2401=(w^2)^2-49^2=(w^2-49)(w^2+49)=(w^2-7^2)(w^2+49)\\\\=(w-7)(w+7)(w^2+49)\\\\------------------------------\\\\a^2-b^2=(a-b)(a+b)
FromTheMoon [43]3 years ago
5 0
w^4-2.401 \\ =(w^2+49)(w^2-49) \\ =(w^2+49)(w-7)(w+7)
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Answer:

Step-by-step explanation:

We want to scale by a factor of 1/10 so |a| = 1/10. This means that the graph is compressed vertically.

We do not reflect across the x axis so a = 1/10.

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<h3>Answer: Choice A</h3>

===============================================

Explanation:

If we replace x with 0, then we get...

f(x) = 3x^2-8x+2

f(0) = 3(0)^2 - 8(0) + 2

f(0) = 3(0) - 8(0) + 2

f(0) = 0 - 0 + 2

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Showing that the input x = 0 leads to the output y = f(x) = 2

The answer is between choice A and choice D because of this. Something like choice B is eliminated because this table shows x = 0 leading to y = -3 which is not correct.

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Let's plug in x = 1

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f(1) = 3(1)^2 - 8(1) + 2

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We don't need to try other x values since we have the answer, but I recommend practicing with other x values to help confirm that the first table is the answer.

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