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yuradex [85]
3 years ago
14

Factor completely w^4-2401

Mathematics
2 answers:
Verdich [7]3 years ago
6 0
w^4-2401=(w^2)^2-49^2=(w^2-49)(w^2+49)=(w^2-7^2)(w^2+49)\\\\=(w-7)(w+7)(w^2+49)\\\\------------------------------\\\\a^2-b^2=(a-b)(a+b)
FromTheMoon [43]3 years ago
5 0
w^4-2.401 \\ =(w^2+49)(w^2-49) \\ =(w^2+49)(w-7)(w+7)
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Suppose that the division N/5 leaves a remainder of 4, and the division N/2 leaves a remainder of 1, what is the ones digit on N
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Since <em>N</em>/2 leaves a remainder, <em>N</em> must be odd and ends with 1, 3, 5, 7, or 9.

<em>N</em>/5 also leaves a remainder, so <em>N</em> is not divisible by 5, so it does not end in 5.

The only correct choice is then 9, since

1 = 0•5 + 1 and 1 = 0•2 + 1

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Alternatively, the given information is equivalent to saying

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