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dezoksy [38]
3 years ago
13

Hey sisters its me James Charles ;)

Mathematics
2 answers:
UNO [17]3 years ago
8 0

Answer:

hey queen

Step-by-step explanation:

Harlamova29_29 [7]3 years ago
8 0

Answer:

hey sisters!!!!!!

Step-by-step explanation:

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PLZ HELP!!!!!! (WILL GIVE BRAINLIEST!!!!)
nasty-shy [4]
I think you times all of the inchs together. 5x3x2=30.

I dont know if i am right tho. Hope this help ya.
3 0
3 years ago
The sum of three numbers is 8. The third is 9
Ierofanga [76]

Answer:

→<u> </u><u>First</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>1</u>

→<u> </u><u>Second</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>2</u>

→<u> </u><u>Third</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>5</u>

Step-by-step explanation:

• let numbers be x, y and z

{ \tt{z = 8y - 9 -  -  - (eqn \: 1)}} \\  \\ { \tt{10x = 8y - 7 -  -  - (eqn \: 2)}} \\  \\ { \tt{x + y + z = 8 -  -  - (eqn \: 3)}}

• from eqn 2, make x the subject:

{ \tt{x =  \frac{8y - 7}{10} }} \\

• substitute all variables in eqn 3:

{ \tt{ \frac{8y - 7}{10}  + y + 8y - 9 = 8}} \\  \\ { \tt{8y - 7 + 10y + 80y - 90 = 80}} \\  \\ { \tt{98y = 177}} \\  \\ { \boxed{ \tt{ \: y = 1.8}}}

• find z

{ \tt{z = 8y - 9}} \\  \\ { \tt{z = 8(1.8) - 9}} \\  \\ { \tt{z = 14.4 - 9}} \\  \\ { \boxed{ \tt{ \: z = 5.4 \: }}}

• find x:

{ \tt{x =  \frac{8(1.8) - 7}{10} }} \\  \\ { \tt{x =  \frac{7.4}{10} }} \\  \\ { \boxed{ \tt{ \: x = 0.74 \: }}}

Rounding to nearest value:

{ \boxed{ \rm{x = 1}}} \\ { \boxed{ \rm{y =2 }}} \\ { \boxed{  \rm{z = 5}}}

7 0
2 years ago
What is the perimeter of a rectangle that is 5.73 feet long and 0.6 feet wide?
sergij07 [2.7K]

Answer:

3.438

Step-by-step explanation:

5.73 × 0.6 = 3.438

3 0
3 years ago
19. A quadratic equation is shown below.
victus00 [196]

Answer:

\{\sqrt b, -\sqrt b\}

Step-by-step explanation:

Given

a^2 - b = 0

Required

Determine the solution

Since b is  a perfect square, the equation can be expressed as:

a^2 - (\sqrt b)^2 = 0

Apply difference of two squares:

(a - \sqrt b)(a + \sqrt b) = 0

Split:

(a - \sqrt b)= 0 \ or\ (a + \sqrt b) = 0

Remove brackets:

a - \sqrt b= 0 \ or\ a + \sqrt b = 0

Make a the subject in both equations

a =\sqrt b \ or\ a  =-\sqrt b

The solution can be represented as:

\{\sqrt b, -\sqrt b\}

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2 years ago
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Morgarella [4.7K]

Answer:

HERES YOUR ASSIGNMENT! I EDITED IT ON MICROSOFT SO THAT I CAN SCREENSHOT IT AND SEND IT TO YOU...I HOPE IT HELPS :)

<h3>ARIGATO OZAIMASU!!!</h3>

6 0
2 years ago
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