In a cafe 4 waitresses can serve 16 tables between them how many could 7 waitresses serve?

Mathematics

1 answer:

nalin [4]3 years ago

4 0

7 waitresses can serve 28 tables

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Luden [163]

<h2>Answer = </h2><h2> $= \frac{1}{y {}^{5} x {}^{2} }$ </h2>

Step-by-step explanation:

Greetings !

simplify for variable y first

apply exponent rule

$a {}^{b} .a {}^{c} = a {}^{b +c \\ } \\ y {}^{ - 8}y {}^{5} = y {}^{ - 8 + 3}$

Add/subtract the numbers -8+3=5

$= y {}^{5}$

Apply exponent rule

$a {}^{ - b} = \frac{1}{a {}^{b} }$

Thus,

$y {}^{ - 5} = \frac{1}{y {}^{5} }$

secondly, simplify for the variable x

Apply exponent rule as we made on y

$x {}^{ - 2}$

$x {}^{ - 2} = \frac{1}{x {}^{2} }$

multiply bot the values we get

Hope it helps!

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1 year ago

Read the following statement: If m∠X≅ m∠Y and m∠Y≅m∠Z then m∠X≅m∠Z. The statement demonstrates:

Ksivusya [100]

The answer is the transitive property

5 0

2 years ago

What is the derivative of the function below?

11111nata11111 [884]

$g(x)=4x-\dfrac{1}{4x}=4x-(4x)^{-1}\\\\\\\\g'(x)=\left[4x-(4x)^{-1}\right]'=(4x)'-\left[(4x)^{-1}\right]'=4-[-1(4x)^{-2}]\cdot4\\\\=4+\dfrac{1}{(4x)^2}\cdot4=4+\dfrac{4}{4^2x^2}=\boxed{4+\dfrac{1}{4x^2}}\\\\Used:\\\\(f(x)-g(x))'=f'(x)-g'(x)\\\\.[f(g(x))]'=f'(g(x))\cdot g'(x)\\\\(x^n)'=nx^{n-1}$