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Dominik [7]
3 years ago
9

In a cafe 4 waitresses can serve 16 tables between them how many could 7 waitresses serve?

Mathematics
1 answer:
nalin [4]3 years ago
4 0
7 waitresses can serve 28 tables
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Help me with this pls
monitta
25 - 8 = 17
She had 17 games at first
hope this helps!
4 0
3 years ago
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Distribute. -3(-2x - 1)
ANTONII [103]

I believe the answer should be 6x+3

6 0
4 years ago
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David wants to measure the width of a road
alexira [117]

Answer:

<u>The width of the road =  25.359 m</u>

Step-by-step explanation:

See the attached figure which represents the problem.

The length of AB = 40 m

let the width of the road w.

Construct PC perpendicular to AB, So, the measure of angle C = 90°

∠B = 60° and ∠A = 45°

Let the length of AC = x, so, the length of BC = 40-x

At ΔBCP which is a right triangle at C

tan B = opposite/adjacent = w/(40-x)

w = (40-x) * tan B  ⇒(1)

At ΔACP which is a right triangle at C

tan A = opposite/adjacent = w/x

w = x * tan A  ⇒(2)

from (1) and (2)

(40-x) * tan B = x * tan A

40 tan B - x *tan B = x tan A

40 tan B  = x tan A + x *tan B

40 tan B  = x (tan A + tan B)

x = (40 tan B)/(tan A + tan B) = (40 tan 60)/(tan 60 + tan 45) = 25.359 m

substitute at (2) with x

w = x tan A = 25.359 tan 45 = 25.359 m

<u>So, The width of the road =  25.359 m</u>

8 0
4 years ago
What is work shown for -6 - 4x =26
Aleks04 [339]

Answer:

x = -8

Step-by-step explanation:

-6 - 4x = 26

- 4x = 32       add 6 to both sides

x = -8        divide both sides by -4 to isolate the variable

4 0
4 years ago
Please help asap!!!!!!
mr Goodwill [35]
<h2>Hello!</h2>

The answer is:

The difference between the areas of the circles will be:

Difference=36\pi -9\pi =27\pi

<h2>Why?</h2>

To find the diffence in area between the two circles, we need to find both areas and then, subtract the smallest circle area to the largest circle area.

So,

For the small circle, we have:

Area_{SmallCircle}=\pi *radius^{2} \\\\Area_{SmallCircle}=\pi *(3)^{2}=9\pi

For the large circle, we have:

Area_{LargeCircle}=\pi *radius^{2} \\\\Area_{LargeCircle}=\pi *(6)^{2}=36\pi

Hence, we have that the difference between the areas of the circles will be:

Difference=36\pi -9\pi =27\pi

Have a nice day!

3 0
4 years ago
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