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Afina-wow [57]
3 years ago
8

Solve the inequality. -z+20>z+20

Mathematics
2 answers:
ehidna [41]3 years ago
7 0
-z+20>z+20\\
-2z>0\\
z
Scilla [17]3 years ago
6 0
-z+20 > z+20\ \ \ \ \ \ |subtract\ 20\ from\ both\ sides\\\\-z > z\ \ \ \ \ |add\ z\ to\ both\ sides\\\\0 > 2z\\\\2z < 0\ \ \ \ \ \ \ |divide\ both\ sides\ by\ 2\\\\z < 0\\\\z\in(-\infty;\ 0)

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If each unit cube has edges of length 1/2 foot what is the volume of the blue outlined prism
postnew [5]

Answer:

The answer is 2.5

Step-by-step explanation:

each cube has a volume of 0.125 and the cube can hold 20 of them.

0.125 * 20 = 2.5

4 0
3 years ago
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Fill in the blanks to solve 48 x 8.<br> 48 x 8<br> = 40 eights + 8<br> eights
kozerog [31]

Question is:

Fill in the blanks to solve \frac{48}{x} =8.

Answer:

x = 6

Step-by-step explanation:

Given

\frac{48}{x} =8

Required

Solve

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x * \frac{48}{x} =8*x

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4 0
3 years ago
At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is
Hitman42 [59]

Answer:

answer = 12.87 km/h

Step-by-step explanation:

Given

Ship A is sailing east at 25 km/h = \frac{dx}{dt}

ship B is sailing north at 20 km/h =\frac{dy}{dt}

here x and y are the  sailing at t = 4 : 00 pm for ship A and B respectively

so we get x = 4 ×25 =100 km/h

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let z is the distance between the ships, we need to find \frac{dz}{dt} at t = 4 hr

At noon, ship A is 130 km west of ship B (12:00 pm)

so equation will be

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z^2 = 30^2 + 80^2\\z =\sqrt{7300} km/h

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2z\frac{dz}{dt} =-2(130-x)\frac{dx}{dt}+2y\frac{dy}{dt}

\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]

\frac{dz}{dt} = \frac{( -20\times25 + 80\times20)}{\sqrt{7300} }

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8 0
3 years ago
Help me pleaseeee pleaseeee
Shtirlitz [24]

Answer:

I think it is 1.5 or 1/2

Step-by-step explanation:

4 0
3 years ago
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IceJOKER [234]
That is how I solved that :)

8 0
3 years ago
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