Answer:
Step-by-step explanation:
Instead, since the divisor is in the form of 
, use what is called Synthetic Division. Remember, in this formula, 
gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:
4| 1 −5 7 −12
↓ 4 −4 12
_______________
1 −1 3 0 →
You start by placing the 
in the top left corner, then list all the coefficients of your dividend [x³ - 5x² + 7x - 12]. You bring down the original term closest to then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an 
, the −1 [
] follows right behind it, and bringing up the rear, comes the 3, giving you the quotient of .
I am joyous to assist you anytime.
Answer:
Frank can put 5 cubes in the box.
Step-by-step explanation:
Formula:
Mass = Volume × density.
1 cubic centimetre = 0.001 liter= 1 millilitre
Given that,
Frank purchase a new ice box having 2 kg capacity.
So,the mass of the cubes is 2 kg.
Each ice cubes measured 3.5 cm by 3.5 cm by 3.5 cm.
The volume of a cube is = 
The volume of a each ice cubes is =
cm³
= 42.875 ml
The ice cubes have a density of 0.914 g/ml
The mass of each cubes are
=volume of each ice cubes × density
=42.875 ml ×0.914 g/ml
=39.18775 gram.
Let x number of ice cubes he can put in the box.
The mass of x cubes is = 39.18775x grams.
2 kg= 2,000 gram [ since 1 kg= 1000 gram]
According to the problem,
39.18775x=2,000
Frank can put 5 cubes in the box.
Answer:
use app Gauthmath its will give you the answer
Answer:
4/52
Step-by-step explanation:
Answer:
10m x 15m
Step-by-step explanation:
You are given some information.
1. The area of the garden: A₁ = 150m²
2. The area of the path: A₂ = 186m²
3. The width of the path: 3m
If the garden has width w and length l, the area of the garden is:
(1) A₁ = l * w
The area of the path is given by:
(2) A₂ = 3l + 3l + 3w + 3w + 4*3*3 = 6l + 6w + 36
Multiplying (2) with l gives:
(3) A₂l = 6l² + 6lw + 36l
Replacing l*w in (3) with A₁ from (1):
(4) A₂l = 6l² + 6A₁ + 36l
Combining:
(5) 6l² + (36 - A₂)l +6A₁ = 0
Simplifying:
(6) l² - 25l + 150 = 0
This equation can be factored:
(7) (l - 10)*(l - 15) = 0
Solving for l we get 2 solutions:
l₁ = 10, l₂ = 15
Using (1) to find w:
w₁ = 15, w₂ = 10
The two solutions are equivalent. The garden has dimensions 10m and 15m.
