You could use the information from part A to get B. I'm not sure if you want A or not, so I'll do it as well.
A
Eo = 10^4.4 Joules
E = 2 * 10^15
Formula
M = (2/3) log (E/Eo)
M = 2/3 * log (2 * 10^15/10^(4.4) )
M = 2/3 * log( 7.9621* 10^10)
M = 2/3 * 10.901
M = 7.26735 on the Richter scale. That is a huge amount of energy.
Part B
Suppose that you use Eo and your base. Eo is 10^4.4
Now the new earthquake is E = 10000 * Eo
So what you get now is M = (2/3)* Log(10000 * Eo / Eo )
The Eo's cancel out.
M = 2/3 * log(10000)
M = 2/3 of 4
M = 8/3
M = 2.6667 difference in the Richter Scale Reading. It is still an awful lot of energy.
What this tells you is that if the original reading was (say) 6 then the 10000 times bigger reading would 8.266667
Answer: M = 2.6667
Answer: y= (x+2)² −
5
Step-by-step explanation:
The way I got this answer is by completing the square. The first step though, when looking at this equation, is to see if we can factor it. The way to check is to look at the coefficient for x² which is 1, and the constant, in this case -1. If we multiply those together, we get −. Now we look at the middle term, 4x. We need to find any numbers that multiply to equal − 1x² and add to 4x. There aren't any, which means it is not factorable.
Hope I helped
Answer:
71
Step-by-step explanation:
Area of fig 1 = 1 x b = 7 x 4 = 28
Area of fig 2 = l x b = (7-2) x 3 = 5 x 3 = 15
Area of fig 1 = 1 x b = 7 x 4 = 28 (same as ig 1)
Area of whole fig = fig 1 + fig 2 + fig 3 = 28+15+28 = 71
I hope im right !!
Answer:
(a) 7.5 seconds
(b) The horizontal distance the package travel during its descent is 1737.8 ft
Step-by-step explanation:
(a) The given function for the height of the object is s = -16·t² + v₀·t + s₀
The initial height of the object s₀ = 900 feet
The initial vertical velocity of the object v₀
= 0 m/s
The time it takes the package to strike the ground is found as follows;
0 = -16·t² + 0×t + 900
900 = 16·t²
t² = 900/16 = 62.25
t = √62.25 = 7.5 seconds
(b) Given that the horizontal velocity of the package is given as 158 miles/hour, we have
158 miles/hour = 231.7126 ft/s
The horizontal distance the package covers in the 7.5 second of vertical flight = 231.7126 ft/s × 7.5 s = 1737.8445 feet = 1737.8 ft to one decimal place
The horizontal distance the package travel during its descent = 1737.8 ft.
