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IceJOKER [234]
3 years ago
11

The total cost after tax to repair Kimber's cracked phone screen is represented by 0.04(30h) + 30h, where h represents the numbe

r of hours it takes to repair kimber's phone. what part of the expression represents the amount of tax she must pay? EXPLAIN YOUR ANSWER IN COMPLETE SENTENCES.
Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
3 0

we are given

The total cost after tax to repair Kimber's cracked phone screen is represented by 0.04(30h) + 30h

where

h represents the number of hours it takes to repair kimber's phone

so,

C=0.04(30h)+30h

we know that

tax will always be some percentage of the entire cost

Here , we have 0.04(30h) ...which means 0.04 of 30h

and 30h is already given

so, 0.04(30h) is 4% of 30h

so, this term must be tax

the expression represents the amount of tax she must pay is 0.04(30h).......Answer

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To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens are buried in soil
Debora [2.8K]

Answer:

statistic value t= 5.43

p-value: < 0.00001.

Step-by-step explanation:

Hello!

To obtain information over the corrosion-resistance properties of a certain type of steel conduit a random sample of 45 specimens was taken and buried for two years.

The study variable is:

X: Max. penetration of a steel conduit.

The data of the sample

n= 45

sample mean X[bar]= 53.4

sample standard deviation S= 4.2

The conduits are manufactured to have a true average penetration of at most 50 mills, symbolically: μ ≤ 50

The hypothesis is:

H₀: μ ≤ 50

H₁: μ > 50

α: 0.05

To choose the corresponding statistic to use to study the population mean, the variable must have a normal distribution. There is no available information to check this, so I'll just assume that the variable has a normal distribution and, since the population variance is unknown and the sample is small, the statistic to use is a Student t.

Under the null hypothesis, the critical region and the p-value are one-tailed.

Critical value:

t_{n-1; 1-\alpha } = t_{44; 0.95} = 1.68

Rejection rule:

Reject the null hypothesis when t ≥ 1.68

t= \frac{53.4 - 50}{\frac{4.2}{\sqrt{45} } }

t= 5.43

The calculated value is greater than the critical value, thedecision is to rject the null hypothesis.

p-value:

P(t ≥ 5.43) = 1 - P(t < 5.43) = < 0.00001.

The p-value is less than α so the decision is to reject the null hypothesis.

Since the null hypothesis was rejected, then the population average of the penetration of the conduits specimens is greater than 50 mils. It is not recommendable to use these conduits.

I hope it helps!

4 0
3 years ago
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