X and y vary directily means
y=kx
72=3k
divide both sides by 3
24=k
k=24
y=72
Answer:
In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.
But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?
Thank you for all of the help.
That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)
So: the two events are not independent, and so that formula doesn't work.
Fortunately, a formula that does work (always!) is:
P(A∪B)=P(A)+P(B)−P(A∩B)
Hence:
P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330
Answer:
8 candy bars
Step-by-step explanation:
Transform the question to an equation:
3 + 2x = 19
Solve:
2x = 16
x = 8
Check the answer:
3 + 2 (8) = 19
3 + 16 = 19
True
L = 2 + .5W
2L + 2W = 40
SOLVING (if needed)
Substitute 2 + .5w in for l in the second equation and solve for w.
2(2 + .5w) + 2w = 40
4 + w + 2w = 40
Combine like terms and subtract 4 from both sides
3w = 36
Divide both sides by 3
w = 12 in.
l = 2 + .5w
l = 2 + .5(12)
l = 8 in.
The length of the SMALLER square is:
B. 5
Basically I tested each answer choice and see if all the information matches it.
Lets check how my answer is correct:
We know that:
The length of the bigger square is 3 more than the smaller square’s length.
The areas of both squares add up to 89 cm^2
length of the SMALLER square is: 5 cm
length of the LARGER square:
5 + 3 = 8 cm
Area of smaller square:
5^2 = 25 cm^2
Area of bigger square:
8^2 = 64 cm^2
ADD UP BOTH AREAS OF SQUARES:
25 + 64 = 89 cm^2
Hope this helps!
