Answer:
the solution is A
Step-by-step explanation:
![\sqrt[3]{27a^{3}b^{7} } \\](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27a%5E%7B3%7Db%5E%7B7%7D%20%20%7D%20%5C%5C)
![\sqrt[3]{(3)^3(a^3)(b^6)b}\\\\3ab^2\sqrt[3]{b}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%283%29%5E3%28a%5E3%29%28b%5E6%29b%7D%5C%5C%5C%5C3ab%5E2%5Csqrt%5B3%5D%7Bb%7D)
Answer:

Step-by-step explanation:

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Answer:

Step-by-step explanation:

Answer:
B.x2-4x=18
x2-4x+4=18+4
Step-by-step explanation:
When you complete the square your quadratic equation must be written in the standard form which is ax^2+bx+c.
First you are going to want to move your c term to the right (in this case move -18 to the right by adding 18 to both sides). This will get you x^2-4x=18. Now you are going to need to complete the square. To complete the square you divide the number in the bx term (in this case -4) by 2 and then square it. (-2^2=4 since a negative times a negative equals a positive). Now that you have 4 you are going to add it to both sides to get x2-4x+4=18+4.