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Luba_88 [7]
3 years ago
6

More Calculus! (I'm so sorry)

Mathematics
1 answer:
Olenka [21]3 years ago
6 0
Recall that converting from Cartesian to polar coordinates involves the identities

\begin{cases}y(r,\phi)=r\sin\phi\\x(r,\phi)=r\cos\phi\end{cases}

As a function in polar coordinates, r depends on \phi, so you can write r=r(\phi).

Differentiating the identities with respect to \phi gives

\begin{cases}\dfrac{\mathrm dy}{\mathrm d\phi}=\dfrac{\mathrm dr}{\mathrm d\phi}\sin\phi+r\cos\phi\\\\\dfrac{\mathrm dx}{\mathrm d\phi}=\dfrac{\mathrm dr}{\mathrm d\phi}\cos\phi-r\sin\phi\end{cases}

The slope of the tangent line to r(\phi) is given by

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm d\phi}}{\frac{\mathrm dx}{\mathrm d\phi}}=\dfrac{\frac{\mathrm dr}{\mathrm d\phi}\sin\phi+r\cos\phi}{\frac{\mathrm dr}{\mathrm d\phi}\cos\phi-r\sin\phi}

Given r(\phi)=3\cos\phi, you have \dfrac{\mathrm dr}{\mathrm d\phi}=-3\sin\phi. So the tangent line to r(\phi) has a slope of

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{-3\sin^2\phi+3\cos^2\phi}{-3\sin\phi\cos\phi-3\cos\phi\sin\phi}=\dfrac{3\cos2\phi}{-3\sin2\phi}=-\cot2\phi

When \phi=120^\circ=\dfrac{2\pi}3\text{ rad}, the tangent line has slope

\dfrac{\mathrm dy}{\mathrm dx}=-\cot\dfrac{4\pi}3=-\dfrac1{\sqrt3}

This line is tangent to the point (r,\phi)=\left(-\dfrac32,\dfrac{2\pi}3\right) which in Cartesian coordinates is equivalent to (x,y)=\left(\dfrac34,-\dfrac{3\sqrt3}4\right), so the equation of the tangent line is

y+\dfrac{3\sqrt3}4=-\dfrac1{\sqrt3}\left(x-\dfrac34\right)

In polar coordinates, this line has equation

r\sin\phi+\dfrac{3\sqrt3}4=-\dfrac1{\sqrt3}\left(r\cos\phi-\dfrac34\right)
\implies r=-\dfrac{3\sqrt3}{2\sqrt3\cos\phi+6\sin\phi}

The tangent line passes through the y-axis when x=0, so the y-intercept is \left(0,-\dfrac{\sqrt3}2\right).

The vector from this point to the point of tangency on r(\phi) is given by the difference of the vector from the origin to the y-intercept (which I'll denote \mathbf a) and the vector from the origin to the point of tangency (denoted by \mathbf b). In the attached graphic, this corresponds to the green arrow.

\mathbf b-\mathbf a=\left(\dfrac34,-\dfrac{3\sqrt3}4\right)-\left(0,-\dfrac{\sqrt3}2\right)=\left(\dfrac34,-\dfrac{\sqrt3}4\right)

The angle between this vector and the vector pointing to the point of tangency is what you're looking for. This is given by

\mathbf b\cdot(\mathbf b-\mathbf a)=\|\mathbf b\|\|\mathbf b-\mathbf a\|\cos\theta
\dfrac98=\dfrac{3\sqrt3}4\cos\theta
\implies\theta=\dfrac\pi6\text{ rad}=30^\circ

The second problem is just a matter of computing the second derivative of \phi with respect to t and plugging in t=2.

\phi(t)=2t^3-6t
\phi'(t)=6t^2-6
\phi''(t)=12t
\implies\phi''(2)=24

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Log 15 (2x − 2) = log 15 (x+9)
notka56 [123]

Answer:

x=11

Step-by-step explanation:

Given the equation

\log_{15}(2x-2)=\log_{15}(x+9)

Note that

2x-2>0\\ \\2x>2\\ \\x>1

and

x+9>0\\ \\x>-9

Combined, x>1

Solve the equation:

2x-2= x+9\\ \\2x-x=9+2\\ \\x=11

Since 11>1, this is the solution to the equation.

5 0
3 years ago
Given g(x) = x^2-x , find g(2/3).<br><br> show work please
castortr0y [4]
I hope this helps you



x=2/3



g (2/3)=(2/3)^2-2/3



g (2/3)= 4/9-2.3/3.3



g (2/3)=4/9-6/9



g (2/3)= -2/9
7 0
3 years ago
It takes omar four minutes to eat eight carrots sticks. how long does it take him to eat one ?
astra-53 [7]
It takes Omar 30 seconds to eat one considering he ate 8 in 4 minutes ...

If we really wanted to we could turn this into the fraction 8/4
8 being the amount of carrot sticks he ate and 4 being the time it took
now all u have to do is simplify that turns into 2/1 and since the 1 is one minute and her can eat 2 in one minute we can safely say he eats 1 carrot stick every 30 seconds 

:) hope this helps!!

5 0
3 years ago
Please help these are not easy for me
Pavel [41]

Answer:

12a^2 - 9a + 5

Step-by-step explanation:

(5a^2 - 6a - 4) - (-7a^2 + 3a - 9)

5a^2 + 7a^2 = 12a^2

-6a - 3a = -9a

-4 + 9 = 5

12a^2 - 9a + 5

7 0
3 years ago
A boat costs $19,200 and decreases in value by 12% per year. How much will the
fomenos
Find 10% of $19,200 = 1,920
Find 2% of $1,920 = 384
12% = $2,304
19,200 - 2,304 = 16,896 (year 1)
Repeat this until you have your 5th year :)
4 0
3 years ago
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