The transformation of a function may involve any change. The correct option is D.
<h3>How does the transformation of a function happen?</h3>
The transformation of a function may involve any change.
Usually, these can be shifted horizontally (by transforming inputs) or vertically (by transforming output), stretched (multiplying outputs or inputs), etc.
If the original function is y = f(x), assuming the horizontal axis is the input axis and the vertical is for outputs, then:
Horizontal shift (also called phase shift):
- Left shift by c units, y=f(x+c) (same output, but c units earlier)
- Right shift by c units, y=f(x-c)(same output, but c units late)
Vertical shift
- Up by d units: y = f(x) + d
- Down by d units: y = f(x) - d
Stretching:
- Vertical stretch by a factor k: y = k \times f(x)
- Horizontal stretch by a factor k: y = f(\dfrac{x}{k})
Given the function f(x)=2ˣ, while the h(x)=-3(2ˣ), therefore, the function f(x) is a reflection and a translation of a function. Hence, the correct option is D.
Learn more about Transforming functions:
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Answer:
well this is very easy all you have to do is divide 4 by 5 and you will get 4 with a remander of 1 or 0.8 or if this was a real life scenario then you could just take that extra slice and cut it in five ways. hope this helped! can i get brainiest plzz? im only ONE away from getting up to expert!
Step-by-step explanation:
Answer:
answer is A
Step-by-step explanation:
Answer:
Choice A
1/17; no, they are dependent events
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Explanation:
There are 13 spades and 52 cards total. So 13/52 = 1/4 is the probability of drawing one spade
If we do not replace the card we pull out, then the probability of another spade is 12/51 since there are 12 spades left out of 51 total.
Multiply the fractions 1/4 and 12/51 to get
(1/4)*(12/51) = (1*12)/(4*51) = 12/204 = 1/17
The two events are not independent because the second event (pulling out a second spade) depends entirely on what happens in the first event (pulling out a first spade). The fact that the probability is altered indicates we have dependent events.
