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3 years ago

Can someone help me I will mark u brilliant for both answers

Mathematics

1 answer:

muminat3 years ago

3 0

Answer:

2) 15.00 + 0.80x

3) 0.90p

Step-by-step explanation:

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Let f(x)=-2x+6 and g(x)=10x-8 <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bf%7D%7Bg%7D%20%28-3%29" id="TexFormula1" title=

tekilochka [14]

Answer:

f(10x-8)=-20x+22

f(g(x))

possibly

g(-2x+6)=-20x+52

g(f(x))

If needing a different answer math-way can possibly help you as it helped me.

6 0

2 years ago

What is the value of x to the nearest tenth? A) 3.3 B) 9.5 C) 8.0 D) 4.7

Alisiya [41]

Answer:

D) 4.7

Step-by-step explanation:

this perpendicular connection with the circle center cuts this intersecting line in half, which is therefore on both sides of x 6.5 long.

I assume 16 is the diameter, so the radius is 8.

therefore, x is one side of the right-angled triangle of

radius

half of the intersecting line

Pythagoras

8² = x² + (6.5)²

64 = x² + 42.25

21.75 = x²

x = 4.7

6 0

2 years ago

PLEASE HELP LIKE RIGHT NOW

Grace [21]

Answer:

Question 21: -6-(-3)

Question 22: -7+12

4 0

3 years ago

Read 2 more answers

When the polynomial is written in standard form, what are the values of the leading coefficient and the constant? 5x + 2 - 3x^2

earnstyle [38]

Leading coefficient = -3
Constant = 2

When you order them in standard form, you need to put them in ascending order of the exponents. Therefore the -3x^2 would come first, which makes the number attached (-3) the lead coefficient.

Also, since the number (2) without an x attached would be last (due to the power of x technically being 0), than that is the constant.

7 0

3 years ago

Test the claim that the mean GPA of night students is larger than 3.1 at the .10 significance level. The null and alternative hy

Alborosie

Answer:

H 0 : μ = 3.1 H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

$t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66$

$df = n-1=75-1 =74$

The p value is:

$p_v = P(t_{74} >8.66) =3.65x10^{-13}$

The significance level is: 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

Step-by-step explanation:

For this case we want to test the claim that mean GPA of night students is larger than 3.1 at the .10 significance level. The claim needs to be on the alternative hypothesis so then we have the following system of hypothesis:

H 0 : μ = 3.1 H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

We have the following info given:

$\bar X = 3.13 , s =0.03 , n =75$

The statistic to check the hypothesis is given by:

$t = \frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}$

Replacing the info given we got:

$t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66$

The degrees of freedom are given by:

$df = n-1=75-1 =74$

The p value since is a right tailed ted is given by:

$p_v = P(t_{74} >8.66) =3.65x10^{-13}$

The significance level is 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

6 0

3 years ago