This information is not enough to tell which of the traits-blood group A or O is dominant.
It is known that blood groups A and B are codominant, which means both will express if found together in a heterozygote. However, blood group O is recessive. But from this information, you can conclude that blood group O is dominant. Why is that so?
Let's imagine that father's genotype is AA and mothers' genotype OO and cross them:
Parents: AA x OO
Offspring: AO AO AO AO
Since we have information that daughter has blood group O, we can conclude that O is dominant over A and mask it. This is not true! In this case, the daughter will have blood group A.
Mother's genotype surely is OO (because O allele is recessive, so to express a recessive trait both alleles must be recessive). But, the father cannot be AA, because it must give O allele to the daughter so she can have genotype OO and blood group O. So, the father's genotype is AO. Let's take a look at that crossing:
Parents: AO x OO
Offspring: AO AO OO OO
Thus, in this case, daughter can have genotype OO and blood group O.
The correct answer to go in the blank would be ''laws''.
Answer:
Phytoplanktons are microscopic creatures that are primary producers of oceans. Phytoplanktons take carbon dioxide from atmosphere to make their food and then they are eaten by some other animals of oceans.
Phytoplanktons are present in huge numbers in oceans and have a great contribution to the carbon cycle because it is responsible for the transfer of carbon dioxide from the atmosphere to the oceans.
Most of the carbon is released through combustion by animals that eat phytoplanktons but some accumulate in the ocean floor because some dead phytoplanktons settles down in the ocean.
Answer:
The answer is 17190 years
Explanation:
Original amount was 5730. To become 1/8 of the original amount, three (3) half life periods will demand because after first half life the amount will become 1/2 and after second half life, amount become 1/2 again (1/2 x 1/2 = 1/4). Third half life, the amount become half 1/2 again (1/2 x 1/2 x 1/2 = 1/8).
For the 3 half life periods we have original amount x numbers of half life periods = 5730 years x 3 = 17190 years
