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2 years ago

To find an approximate value for a number

Mathematics

1 answer:

Nitella [24]2 years ago

7 0

Remove the negative sign usually. Hope this helps!

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The number of words defined on pages randomly selected from a dictionary are given below. Find the range and standard deviation

faltersainse [42]

Answer: The range of the set of numbers is 46 and the standard deviation is 14.44 .

Explanation:

In is given that the observations are 65, 59, 43, 43, 40, 63, 71, 77, 31, 64.

From given data it is noticed that the highest observation is 77 and the lowest observation is 31.

Range = Highest observation - Lowest observation

Range = 77 - 31 = 46

To find the standard deviation, first we have to find the mean.

$\text{Mean}={\frac{\text{Sum of observation}}{\text{Total number of observations}}$

Total of the observations is 556 and number of observation is 10.

$\text{Mean}=\frac{556}{10}=55.6$

Formula fr standard deviation is,

$\sigma =\sqrt{\frac{\sum (x-mean)^2}{n}}$

To find the above values form a table as shown below.

$\sigma =\sqrt{\frac{2086.4}{10}}$

$\sigma =\sqrt{208.64}$

$\sigma =14.44$

Therefore, the range of the set of numbers is 46 and the standard deviation is 14.44 .

7 0

2 years ago

6 apples 4 bananas 3 carrots cost 2.93$ 4 apples 4 bananas and 2 carrots cost 2.22$ 8 carrots cost 0.88$ how much is each item

GarryVolchara [31]

Answer:

Step-by-step explanation:

carrot = 0.11 $ .ie 0.88/8

3 0

2 years ago

Situation:A researcher in North America discoversa fossile that contains 65% of its originalamount of C-14..-ktN=NoeNo inital am

zheka24 [161]

SOLUTION

We have been given the equation of the decay as

$\begin{gathered} N=N_0e^{-kt} \\ where\text{ } \\ N_0=initial\text{ amount of C-14 at time t} \\ N=amount\text{ of C-14 at time t = 65\% of N}_0=0.65N_0 \\ k=0.0001 \\ t=time\text{ in years = ?} \end{gathered}$

So we are looking for the time

Plugging the values into the equation, we have

$\begin{gathered} N=N_0e^{-kt} \\ 0.65N_0=N_0e^{-0.0001t} \\ e^{-0.0001t}=\frac{0.65N_0}{N_0} \\ e^{-0.0001t}=0.65 \end{gathered}$

Taking Ln of both sides, we have

$\begin{gathered} ln(e^{-0.000t})=ln(0.65) \\ -0.0001t=ln(0.65) \\ t=\frac{ln(0.65)}{-0.0001} \\ t=4307.82916 \end{gathered}$

Hence the answer is 4308 to the nearest year

8 0

1 month ago

A researcher decides to determine if the type of writing utensil that a student uses while doing their math affects their accura

alexandr1967 [171]

Since the variable type of writing utensil assumes labels and not numbers, it is classified as qualitative.

<h3>What are qualitative and quantitative variables?</h3>

Qualitative variables: Assumes labels or ranks.

Quantitative variables: Assume numerical values.

In this problem, the type of writing utensil has 4 labels: regular pencil, mechanical pencil, pen, whatever.

Hence, since the variable assumes labels and not numbers, it is classified as qualitative.

More can be learned about quantitative and qualitative variables at brainly.com/question/20598475

5 0

2 years ago

What is the value of 4.5 x 10^5 written in standard form?

soldier1979 [14.2K]

Answer:

4500000

Step-by-step explanation: Let me know if this helped

3 0

2 years ago