3 years ago

To find an approximate value for a number

Mathematics

1 answer:

Nitella [24]3 years ago

7 0

Remove the negative sign usually. Hope this helps!

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Please help me<br> Expressions

11111nata11111 [884]

1a= (2x+5)+3x+15

1b= (2(4)+5)+3(4)+15=40

2a= (3x+5)•(4x-3)

2b= (3(2)+5)•(4(2)-3)=55

2c= 2(x) or 2(2)

How I got 2c is the perimeter of the rectangle LMNP subtract from (2(2)+9)+(2(2)+9)=26 which in return means you subtract 30 from 26 and get 4 which is 2(2) or 2x

6 0

3 years ago

Sanjay graphs a quadratic function that has x-intercepts of –3 and 7. Which functions could he have graphed?

kykrilka [37]

we will select each options and find zeros

(a)

$g(x)=x^2-4x-21$

for finding x-intercept , we can set g(x)=0

and then we can solve for x

$g(x)=x^2-4x-21=0$

now, we can factor it

$(x-7)(x+3)=0$

we get

$x=7,x=-3$

so, this is TRUE

(b)

$g(x)=(x-3)(x+7)$

we can set it to 0

and then we can solve for x

$g(x)=(x-3)(x+7)=0$

we get

$x=3,x=-7$

so, this is FALSE

(c)

$g(x)=3x^2-12x-63$

we can set it to 0

and then we can solve for x

$g(x)=3x^2-12x-63 =0$

$3(x^2-4x-21) =0$

$3(x-7)(x+3) =0$

$x=-3,x=7$

so, this is TRUE

(d)

$g(x)=-(x+3)(x-7)$

now, we can set it to 0

and then we can solve for x

$g(x)=-(x+3)(x-7)=0$

$x=-3,x=7$

so, this is TRUE

(e)

we have

$g(x)=x^2+4x-21$

now, we can set it to 0

and then we can solve for x

$g(x)=x^2+4x-21=0$

$(x+7)(x-3)=0$

$x=-7,x=3$

so, this is FALSE

5 0

2 years ago

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Suppose somebody writes down an equation for a 5th-degree polynomial function in standard form and tells you that it has only on

Vlada [557]

The answer & explanation for this question is given in the attachment below.

4 0

3 years ago

Please answer ALL of the following if you do so i will give you brainiest :))))) :

chubhunter [2.5K]

2x^2 if x=1/8 is 1/16
4x^2 if x=1/8 is 1/2

8 0

2 years ago

Read 2 more answers

A map has a scale of 1cm:20 km two cities are 2.5 cm apart on the map to the nearest tenth of a kilometer what is the actual dis

Aleksandr-060686 [28]

Answer: 50 km

Step-by-step explanation: So the map has a scale of 1 cm: 20 km. Next, you look at how far they are apart and see if the scale and the distance on the map are the same measurement. In this case, they are both centimeters so they stay the same. Then, all you do is multiple the real size, 20 km, by

2.5 /1 . Then, 20 x 2.5=50. So the answer is 50 km

6 0

3 years ago