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coldgirl [10]
3 years ago
6

How to write a real world problem that could be solved using proportions

Mathematics
2 answers:
julsineya [31]3 years ago
6 0
You could used building measurements, like the building is 85 ft tall and 45 ft wide, and the second build is 67 ft tall, find the width of the second building. Set up a proportion with the first building measurements and the second building measurements using x for the missing width.
Debora [2.8K]3 years ago
4 0
U can use  real world numbers and problems to help 
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allsm [11]
Nadia

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3 years ago
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kaheart [24]
Answer:
1. Step 2: 2a-6+6 Step 3: 2a
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Step by step explanation:
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6 0
3 years ago
How does the rate of change vary from point to point?
Tpy6a [65]

\bf \begin{array}{|cc|ll} \cline{1-2} x&y\\ \cline{1-2} 40&32\\ 28&16\\ 16&12\\ \cline{1-2} \end{array}~\hfill \stackrel{\textit{average rate of change}}{slope} \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{40}~,~\stackrel{y_1}{32})\qquad (\stackrel{x_2}{28}~,~\stackrel{y_2}{16}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{16-32}{28-40}\implies \cfrac{-16}{-12}\implies \boxed{\cfrac{4}{3}} \\\\[-0.35em] ~\dotfill

\bf (\stackrel{x_1}{28}~,~\stackrel{y_1}{16})\qquad (\stackrel{x_2}{16}~,~\stackrel{y_2}{12}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{12-16}{16-28}\implies \cfrac{-4}{-12}\implies \boxed{\cfrac{1}{3}}

8 0
3 years ago
How do u do this plz help me, also can some one tell me what is a adjacent angle and a vertical angle plz
Vsevolod [243]
Adjacent AnglesTwo angles areAdjacent if they have a common side and a common vertex. ... VerticalAnglesVertical Angles are the anglesopposite each other when two lines cross.They are called "Vertical" because they share the same Vertex.Vertical Angles are Congruent/equivalent
6 0
3 years ago
Find the equation that passes through points A and B
Irina18 [472]

Answer:

Step-by-step explanation:

A(1,7); B(-3,-1); slope m =(-1-7)/-3-1) = -8/-4 = 2

Equation of a line AB is

((y-y1) = m(x-x1)

y - 7 = 2(x-1)

y - 7 = 2x-2

y = 2x + 5

3 0
2 years ago
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