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3 years ago

NEED SOMEONE WITH BIG BRAINS

Mathematics

1 answer:

seropon [69]3 years ago

3 0

Answer: just an extra one foot

Step-by-step explanation:

Given that the length of the piece of string = 25,000 miles

Since the string is long enough to exactly circle the globe at the equator over oceans, deserts and jungles. We can say that the string could completely circle a sphere

Assuming that the earth is a perfect sphere.

The circumference of the circle = 25,000 mile.

But note that the circumference of a circle is directly proportional to the radius. If you double the radius, the circumference will also be doubled. Half the circumference, half the radius. Increase the circumference by 30%, radius will also be increased by 30% and so on.

In this question, the radius is being increased by 3 feet, so we need to know that as a fraction of the original radius.

Circumference = 2πr

Let's also convert miles to feet

25000 × 5280 = 2(3.143)r

r = 132 × 10^6/2π

r = 21008452.5 feet

3 feet - that's how far off the ground we're lifting the string out of 21008452.5 feet is close to one part in 25000 miles. The string was 132000000 feet long to start with, so we need just an extra 1 foot.

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uysha [10]

Answer:

The perimeter of the trapezoid is $38.25\ units$

Step-by-step explanation:

we know that

The perimeter of the trapezoid is the sum of its four side lengths

In this problem

$P=QR+RS+ST+QT$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$Q(8, 8), R(14, 16), S(20, 16),T(22, 8)$

step 1

Find the distance QR

$Q(8, 8), R(14, 16)$

substitute the values in the formula

$d=\sqrt{(16-8)^{2}+(14-8)^{2}}$

$d=\sqrt{(8)^{2}+(6)^{2}}$

$d=\sqrt{100}$

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step 2

Find the distance RS

$R(14, 16), S(20, 16)$

substitute the values in the formula

$d=\sqrt{(16-16)^{2}+(20-14)^{2}}$

$d=\sqrt{(0)^{2}+(6)^{2}}$

$d=\sqrt{36}$

$RS=6\ units$

step 3

Find the distance ST

$S(20, 16),T(22, 8)$

substitute the values in the formula

$d=\sqrt{(8-16)^{2}+(22-20)^{2}}$

$d=\sqrt{(-8)^{2}+(2)^{2}}$

$d=\sqrt{68}$

$ST=8.25\ units$

step 4

Find the distance QT

$Q(8, 8),T(22, 8)$

substitute the values in the formula

$d=\sqrt{(8-8)^{2}+(22-8)^{2}}$

$d=\sqrt{(0)^{2}+(14)^{2}}$

$d=\sqrt{196}$

$QT=14\ units$

step 5

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$P=10+6+8.25+14=38.25\ units$

6 0

3 years ago

Read 2 more answers

ANSWER AND EXPLAIN IF UR RIGHT ILL MARK U BRAINLIEST!!!

guapka [62]

Answer:

Step-by-step explanation:

B and D are congruent. Set them equal to each other.

15x + 5 = 16x - 2

x = 7

Plug into B.

15(7) + 5 = 110

180 - 110 = 70

12y + 10 = 70

12y = 60

60 / 12 = 5 = y

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3 years ago

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notka56 [123]

Answer:

8) 10°

9) X can not be determined.

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Step-by-step explanation:

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So, 6x = 60°

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Therefore, each angle is 60°.

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So, 3x + 8 = 4x - 4

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zaharov [31]

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