Standard form of an exponential function is y=ab^x
when x=0, y=3, 3=ab^0, so you can figure out that a=3
when x=-1, y=6, 6=3b^(-1), b^(-1)=2, b=1/2
so the equation is y=3(1/2)^x
Answer:
<h2>
w = -8</h2>
Step-by-step explanation:
Given the equation solved by Ernesto expressed as
, the extraneous solution obtained by Ernesto is shown below;
![\sqrt{\dfrac{1}{2}w+8}=-2\\\\square\ both \ sides \ of \ the \ equation\\(\sqrt{\dfrac{1}{2}w+8})^2=(-2)^2\\\\\dfrac{1}{2}w+8 = 4\\\\Subtract \ 8 \ from \ both \ sides\\\\\dfrac{1}{2}w+8 - 8= 4- 8\\\\\dfrac{1}{2}w= -4\\\\multiply \ both \ sides \ by \ 2\\\\\dfrac{1}{2}w*2= -4*2\\\\w = -8](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cdfrac%7B1%7D%7B2%7Dw%2B8%7D%3D-2%5C%5C%5C%5Csquare%5C%20both%20%5C%20sides%20%5C%20of%20%5C%20the%20%5C%20equation%5C%5C%28%5Csqrt%7B%5Cdfrac%7B1%7D%7B2%7Dw%2B8%7D%29%5E2%3D%28-2%29%5E2%5C%5C%5C%5C%5Cdfrac%7B1%7D%7B2%7Dw%2B8%20%3D%204%5C%5C%5C%5CSubtract%20%5C%208%20%5C%20from%20%5C%20both%20%5C%20sides%5C%5C%5C%5C%5Cdfrac%7B1%7D%7B2%7Dw%2B8%20-%208%3D%204-%208%5C%5C%5C%5C%5Cdfrac%7B1%7D%7B2%7Dw%3D%20-4%5C%5C%5C%5Cmultiply%20%5C%20both%20%5C%20sides%20%5C%20by%20%5C%202%5C%5C%5C%5C%5Cdfrac%7B1%7D%7B2%7Dw%2A2%3D%20-4%2A2%5C%5C%5C%5Cw%20%3D%20-8)
Hence, the extraneous solution that Ernesto obtained is w = -8
12.6/ .6= 21. The only way i no to show the work is tojust writetheproblem
Y=(1/4)x
take the number and multiply it by 1/4
36% in decimal from it .36
172.80 + .36 = 173.16
So original price was 173.16