Answer:
you wont
Step-by-step explanation:
12.28 = 12 and 28 hundredths so its 12
![\frac{28}{100}](https://tex.z-dn.net/?f=%20%5Cfrac%7B28%7D%7B100%7D%20)
Hope I helped!
The answer is B, because 0.06*45000 + 0.08(51000-45000) = 3,180
Answer:
D. n=7; u=12; m=14
Step-by-step explanation:
Check the offered answers against the problem statement. Only choice D has 5 more used than new books.
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The prices are unused in answering the question. They can be ignored.
<span> For this case we have an expression of the form:
</span>
![\sqrt[4]{16x^{11}y^8}/(81x^7y^6)](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B16x%5E%7B11%7Dy%5E8%7D%2F%2881x%5E7y%5E6%29%20)
To solve the problem, we must rewrite the expression using properties of exponents.
Rewriting the expression we have:
![\sqrt[4]{2^4x^8x^3y^8}/(81x^7y^6)](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B2%5E4x%5E8x%5E3y%5E8%7D%2F%2881x%5E7y%5E6%29%20)
Then, by root properties we have:
![2x^2y^2(\sqrt[4]{x^3})/(81x^7y^6) ](https://tex.z-dn.net/?f=%202x%5E2y%5E2%28%5Csqrt%5B4%5D%7Bx%5E3%7D%29%2F%2881x%5E7y%5E6%29%0A)
Then, by power properties again:
![2(\sqrt[4]{x^3})/(81x^5y^4)](https://tex.z-dn.net/?f=%202%28%5Csqrt%5B4%5D%7Bx%5E3%7D%29%2F%2881x%5E5y%5E4%29%20)
Answer:
An <span>expression that is equivalent is:
</span>