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Dmitrij [34]
3 years ago
8

A baker has 14.6 pounds of flour and 5 5/4 pounds of butter.How many more pounds of flour than butter does the baker have.

Mathematics
1 answer:
navik [9.2K]3 years ago
6 0

Answer:

8.35

Step-by-step explanation:

Butter : 5 5/4 = 25/4 = 6.25

Flour - Butter = 14.6 - 6.25

= 8.35

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A single tree produces about 2.6 × 102 lb of oxygen each year. The Amazon rainforest has about 3.9 × 1011 trees.
ankoles [38]

(2.6 x 10² lb/tree) x (3.9 x 10¹¹ tree) = 1.014 x 10¹⁴ pounds .

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What is the sum of the infinite geometric series? Sigma-Summation Underscript n = 1 Overscript 4 EndScripts (negative 144) (one-
Irina18 [472]

The sum of the infinite geometric series is -288.

<h2>Given that</h2>

A finite geometric series with n = 4, a₁ = -144, and r = ½.

<h3>We have to determine</h3>

What is the sum of the infinite geometric series?

<h3>According to the question</h3>

The sum of the infinite is determined by the following formula;

\rm S\infty = \dfrac{a_1(1-r^n)}{1-r}\\\\

A finite geometric series with n = 4, a₁ = -144, and r = ½.

Substitute all the values in the formula;

\rm S\infty = \dfrac{a_1(1-r^n)}{1-r}\\\\S\infty = \dfrac{-144 (1- \dfrac{1}{2}^4)}{1-\dfrac{1}{2}}\\\\S \infty = \dfrac{-144 \times \dfrac{15}{16}}{\dfrac{1}{2}}\\\\S \infty = -270

Therefore,

The sum of the infinite geometric series is,

\rm S = \dfrac{a_1}{1-r}\\\\S=\dfrac{-144}{1-\dfrac{1}{2}}\\\\S = \dfrac{-144}{0.5}\\\\S = -288

Hence, the sum of the infinite geometric series is -288.

To know more about Geometric Series click the link given below.

brainly.com/question/16037289

5 0
2 years ago
At Baceball practice, Asher caught 16 of 20 hits to the out field. Select all of the was of expressing 16 out of 20. a. 3/5 b. 0
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Answer:

16 : 20 = 0,8 = 80%

Step-by-step explanation:

pls make me a brinist

3 0
3 years ago
Explain how System 1 becomes equivalent to System 2.
LenKa [72]

Answer:

In the procedure

Step-by-step explanation:

we have

<em>System 1</em>

Ax+By=C -----> equation A

Lx+My=N -----> equation B

<em>step 1</em>

Multiply equation B by -1 both sides

(-1)*(Lx+My=)N*(-1)

-Lx-My=-N ------> equation C

<em>step 2</em>

Adds equation A and equation C

Ax+By=C

-Lx-My=-N

----------------

Ax-Lx+By-My=C-N

(A-L)x+(B-M)y=C-N -----> equation D

step 3

An equivalent system (System 2) is formed with

Ax+By=C -----> equation A

(A-L)x+(B-M)y=C-N -----> equation D

6 0
3 years ago
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