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dsp73
3 years ago
6

Solve the following system of equations by the substitution method. 10x+10y=1.

Mathematics
1 answer:
Klio2033 [76]3 years ago
8 0

Answer:

Since one equation already has one variable isolated(x), it gives you a "value" to input into the other equation to use to solve for the other variable(y).

10(y-3) + 10y = 1

10y - 30 + 10y = 1

20y - 30 = 1

20y = 31

y = 31/20 or 1.55

Now you can use this value to solve for x in one of the original equations.

x = (31/20) - 3

x = -29/30 or -1.45

Hope this helps!

Step-by-step explanation:

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7 0
3 years ago
Multiply -4x^-2y(2yx^3+6xy^3-3y^3x4)
Alenkinab [10]

Answer:

below here hopes it helps!

Step-by-step explanation:

8 0
2 years ago
17. The area of a rectangular sandbox is 8x2 + 18x + 9. If one of it's dimensions is (2x + 3), what is the other
Natasha2012 [34]

Answer:

The other dimension of the sandbox must be (4x+3).

Hope this helps! Have a good day!

6 0
2 years ago
16. Solve the equation. Check the solution.
harina [27]
Hi there

a/(a² - 36) + 2/(a-6) = 1/(a+6)
a/(a+6)(a-6) + 2/(a-6) = 1/(a+6)
Now we need to multiply the terms by (a+6)(a-6)
a + 2(a+6) = 1(a-6)
a + 2a + 12 = a - 6
3a + 12 = a - 6
3a - a = -6 - 12
2a = -18
Divide both sides by 2
2a/2 = -18/2
a = -9
Thus, The correct option is A


I hope that's help !

Good luck !

 
8 0
3 years ago
Is y=3x-5 and 6x=2y+10 a solution
iVinArrow [24]
Y=3x-5
y-3x=-5
Times 2 from both side
y(2)-3x(2)=-5(2)
2y-6x=-10
Times negative from both side
(-)2y-6x(-)=(-)-10
-2y+6x=10
or
6x-2y=10


6x=2y+10
6x-2y=10
Furthermore, we see that both equation have the same 6x-2y=10 which means that both of them have infinity solutions, not a solution. Hope it help!
5 0
3 years ago
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