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3 years ago

Which statement defines a function correctly

Mathematics

1 answer:

Brut [27]3 years ago

5 0

Answer:

A function gives for each element of the domain only one element of the range.

Step-by-step explanation:

We have to choose from the statements in the options that define a function correctly.

From my point of view the statement that a function gives for each element of the domain only one element of the range, defines a function properly.

Geometrically it represents that if we draw a vertical line in the graph of the function that intersects the graph at more than one points then this is not a function, this is only a relation. (Answer)

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Katherine goes to the deli to buy some turkey. Turkey cost $5.28 per pound. Katherine needs to buy 3 1/4 pounds of turkey. How m

Leto [7]

5.28 dollars per pound multiplied by 3.25 pounds is a total of 3.25*5.28=$17.16.

7 0

2 years ago

Find the discriminant of the following quadratic equation then state the number of rational, irrational, and imaginary solutions

lianna [129]

Answer:

-6x² - 6 = -7x - 9
-6x² + 7x - 6 + 9 = 0
-6x² + 7x + 3 = 0
6x² - 7x - 3 = 0

Discriminant:

D = (-7)² - 4*6*(-3) = 49 + 72 = 121

Since D > 0, there are 2 real solutions:

x = (- (-7) ±√121 )/12
x = (7 ± 11)/12
x = 1.5, x = -1/3

8 0

2 years ago

Read 2 more answers

15y^-11/3y^-11, show steps I need help please don't understand how to do it.

tester [92]

One may note, you never quite asked anything per se, ahemm, if you meant simplification.

$\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\
-------------------------------\\\\
\cfrac{15y^{-11}}{3y^{-11}}\implies \cfrac{15}{3}\cdot \cfrac{y^{-11}}{y^{-11}}\implies 5\cdot y^{-11}\cdot y^{+11}\implies 5\cdot y^{-11+11}
\\\\\\
5y^0 \implies \boxed{5}$

8 0

3 years ago

I will like to know how to solve this

Alexxandr [17]

This is a linear equation in x.

So you need to group like terms

$1 + 4x = - 5 + 7x$
Let us group the x terms on the Right Hand Side of the equation and the constant terms on the Left Hand Side.

$1 + 5 = 7x - 4x$
We can now simplify

$6 = 3x$
Now let us divide both sides by 3.

$\frac{6}{3} = \frac{3x}{3}$

This implies that

$2 = x$
or

$x = 2$
Let us our answer

$1 + 4(2) = - 5 + 7(2)$

$1 + 8 = - 5 + 14$
$9 = 9$
Good we are right

5 0

3 years ago

Read 2 more answers

HCF AND LCM of 32 and 48 using the prime factorisation

torisob [31]

Answer:

Below.

Step-by-step explanation:

32 = 2*2*2*2*2

48 = 2*2*2*2*3

So The GCF = 2*2*2*2 = 16.

LCM = 2*2*2*2*2*3 = 96

3 0

2 years ago