1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vladimir2022 [97]
3 years ago
5

Solve the system by substitution. Check your solution.

Mathematics
1 answer:
zvonat [6]3 years ago
4 0
B. (9,126)

<span>y + 18 = 16x
=>y=16x-18 
0.5x + 0.25y = 36 (multiply both sides by 4)
=>2x+y = 144
Substitute y=16x-8

=>2x+16x-8=144
=>18x=152
=>x=152/18=9 
y=16x-18
=>y=16(9)-18
=>y=144-18=126 
Answer: x=9 and y=126</span>
You might be interested in
Enter a formula using k to connect the two variables.
LenKa [72]

Answer:

Weres The Formula?

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Youre amazing!!! could you help me? 50 points!!! Write an expression that can be used to produce vector d from vector c, and exp
andrew-mc [135]

Answer:

Multiply vector c by the scalar -1/2.

Step-by-step explanation:

Look at vector c.

It has an x component of 4 and a y component of 4.

You can write vector c as a sum of its components using unit vectors in the x direction (i) and in the y direction (j).

c = 4i + 4j

Now look at vector d, and write it also as a sum of its x and y components.

d = -2i - 2j

Now ask yourself, what operation do I do to 4 to end up with -2?

One answer is to multiply 4 by -1/2.

d = (-1/2)c = (-1/2)(4i) + (-1/2)(4j) = -2i - 2j

That worked. By multiplying vector c by the scalar -1/2, you end up with vector d.

8 0
2 years ago
609.9 is 85% of what number
castortr0y [4]
Hi

609.9 ⇒ 85%
x ⇒ 100%

85x = 100·(609.9)
85x = 60,990
x = (60,990)/85
x = 717.5294117... ≈ 717.53

85% of 717.53 ⇒ 0.85 × 717.53 = 609.9005 ≈ 609.9

Answer: 717.53
7 0
3 years ago
Read 2 more answers
A school wants to add a new sports team. The school sent out surveys asking for the​ students' favorite sport. Twelve students n
rjkz [21]
Divide 100 by 48 and you should get how many people per percent, then multiply by 100 and boom.
3 0
3 years ago
Read 2 more answers
Quadrilateral LMNO is similar to quadrilateral PQRS. Find the measure of side QR.
dalvyx [7]

Answer:

The measure of the side QR is 8.8.

Step-by-step explanation:

Since LMNO \sim PQRS, then SP \propto OL, RS \propto ON, RQ \propto MN and QP \propto LM. From figure we have the following relationship:

k = \frac{OL}{SP} = \frac{ON}{RS} = \frac{MN}{QR} = \frac{ML}{QP} (1)

Where k is the proportionality ratio.

If we know that SP = 13, OL = 55, MN = 37, then the measure of side QR is:

k = \frac{OL}{SP} (1b)

k = \frac{55}{13}

k = \frac{MN}{QR}

QR = \frac{MN}{k} (1c)

QR = \frac{37}{\frac{55}{13} }

QR = 8.745

The measure of the side QR is 8.8.

4 0
3 years ago
Other questions:
  • Solving a word problem with two unknown using a linear equation
    15·1 answer
  • TEA samples its test questions for the TAKS test every year by field testing the questions. they tell schools to test certain cl
    9·1 answer
  • One day, I decide to run to the park. On the way there, I run at a rate of x^2 miles per hour for 3 hours. On the way back, I ta
    6·2 answers
  • What’s the answer to this?
    13·1 answer
  • 2^1/2 x 3^2/3 in simplest form hurry help im on my test!!!!!!! Will mark as brainliest!
    9·2 answers
  • Luis makes 3 free throws out of every 7 shots how many free throws will he make if he shoots 21 times
    13·1 answer
  • John has 260. Apples 1/2 of the apples are green and 1/4. Of the apples are bad. The rest of the apples are red How many red app
    7·1 answer
  • Which statement is true for the values of Pand Q on this number line? + Q + -2 1 -4 -3 0 1 A 응 4 B. PxQ5 C P+Q&gt; -4 D P - Qo​
    6·1 answer
  • Pls help me with this question!!
    11·1 answer
  • Stanley’s father is paying for a $20 meal. He has a 15% off coupon for the meal. With the discount, how much is the meal?
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!