Question

Franklin rolls a pair of six-sided fair dice with sides numbered 1 through 6.

Answer 1

Answer:

I got 11/18 for the first one and 5/9 for the second one...

Hope this helps :)

Step-by-step explanation:

Answer 2

Answer:

11/18

5/9

Step-by-step explanation:

Make a table showing all the possible sums for two dice:

$\left[\begin{array}{ccccccc}&1&2&3&4&5&6\\1&2&3&4&5&6&7\\2&3&4&5&6&7&8\\3&4&5&6&7&8&9\\4&5&6&7&8&9&10\\5&6&7&8&9&10&11\\6&7&8&9&10&11&12\end{array}\right]$

Of the 36 possible sums, 18 are even, 7 are multiples of 5, and 3 are both even and multiple of 5.  So the probability is:

P(even or multiple of 5) = (18 + 7 − 3) / 36 = 22/36 = 11/18

Of the 36 possible sums, 12 are multiples of 3, 9 are multiples of 4, and 1 is a multiple of both 3 and 4.  So the probability is:

P(multiple of 3 or 4) = (12 + 9 − 1) / 36 = 20/36 = 5/9